Explanation:
It is given that,
Diameter of the circular loop, d = 1.5 cm
Radius of the circular loop, r = 0.0075 m
Magnetic field, 
(A) We need to find the current in the loop. The magnetic field in a circular loop is given by :



I = 32.22 A
(b) The magnetic field on a current carrying wire is given by :



r = 0.00238 m

Hence, this is the required solution.
Answer:
0.0239364 N
0.0057879 N
Explanation:
= Density of the gas
g = Acceleration due to gravity = 9.81 m/s²
V = Volume
Mass of rubber = 1.5 g
Buoyant force is given by

The buoyant force is 0.0239364 N
Net vertical force is given by

The net vertical force is 0.0057879 N
The third law of thermodynamics,the principle of temperature.
This law states that the entropy at 0 is always equel to 0.
This means that it is impossible to cool down a perfect 0 or absolute 0(-273.15 C)
The change in potential energy of an object is given by

where
m is the mass of the object
g is the gravitational acceleration

is the increase in altitude of the object
In our problem,

is the mass of the book,

and

is the increase in altitude of the book, so its variation of potential energy is