How many yards are in 2 millimeters

1 answer:

7 0

In 1 millimeter, there are 0.00109361
So in 2 mm, there are 2 × 0.00109361 = 0.00218722 yards

or do proportions:
$\frac{1mm}{0.00109361yd}$ = $\frac{2}{y}$

Cross multiply:

2 × 0.00109361 = y
0.00218711 = y

0.00218722 yards are in 2 millimeters.

You might be interested in

Write 375 as the product of prime factors .<br> Give your answer in index form

gtnhenbr [62]

Answer:

3•5•5•5

Step-by-step explanation:

hey dude wassup shviika shekar here :) i want to let u know this is actually rpetty simple just think and list of prime numbers and do it yes it take time but...

8 0

3 years ago

Please help!!! the question is in the picture above— this is geometry

Serga [27]

Use the co‐interior rule, corresponding angle rule, alternate angle rule and vertical opposite angle rule to solve the question above.

angle G5 = angle K1 reason : corresponding angles

angle J1 = angle H3 reason: vertical opposite angles

angle J2 = angle K4 reason: vertical opposite angles

angle G5 = angle K4 reason: co‐ interior angles

angle F6 = angle K4 reason: alternate angle

8 0

3 years ago

Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ

mrs_skeptik [129]

Answer:

Step-by-step explanation:

If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm...

Anyways, the half angle identity for tangent is

$tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}$

There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one.

If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:

$tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }$ which simplifies a bit to