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tensa zangetsu [6.8K]
3 years ago
13

Show how to solve the problem 378 times 6 using place value with regrouping. Explain how you knew when to regroup

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0

300*6 + 70*6 + 8*6

1800 + 420 + 48

2268


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The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the pro
Bogdan [553]

Answer:

Step-by-step explanation:

Let X be the length of pregnancy.

X is N(268, 15)

a) Prob of pregnancy lasting 307 days or longer

= P(X>307) = P(Z>\frac{307-268}{15} )\\=P(Z>2.6)\\

=0.5-0.4953

=0.0047

b) Lowest 2% is 2nd percentile

Z=-2.55

X score = 268-2.55(15)

= 229.75 days

If length of days >230 days then it is not premature.

4 0
3 years ago
Can some one solve this
Roman55 [17]
Well, first you have to convert to one unit... then simplify
D:H
150m:16500cm
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30:33
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7 0
3 years ago
The distance from the center of a carousel to the
anzhelika [568]

Answer:

\fbox{\begin{minipage}{3.5em}338 (ft)\end{minipage}}

Step-by-step explanation:

The problem could be simplified as following:

Given:

The radius of a circle O is 26 feet.

Solve for:

The length of arc on circle O that measures 13 radians

Solution:

Step 1: Let's find out the correct formula to apply:

The formula to calculate the length of an arc measuring x radians on a circle with radius r feet is:

L = r*x

Step 2: Let's put the data into formula to work out the length L of arc:

L = 26*13 = 338 (ft)

=>  The distance that a horse does on the outer edge travel  when the carousel rotates through 13 radians: L = 338 (ft)

Hope this helps!

:)

7 0
3 years ago
Find the Slope using the Slope Formula ​
ExtremeBDS [4]
Answer: -1

2-1=1
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7 0
3 years ago
Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm
Oksi-84 [34.3K]

\boxed{91mm

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m

Therefore, we can compute the following:

\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m

Writing this in increasing order:

0.091m

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

7 0
3 years ago
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