He can buy 1 1\4 ounce for a dollar or 1.25 ounces or depending on your answer choice 1 ounce. All those answer are right
Answer:
irrational
Step-by-step explanation:
because an irrational number goes on forever so no matter what number is added to it it will always be irrational.
Here, we are required to determine how many hours your friend will drive in order to catch you.
(a)<em> Your friend will have to drive 7 and a half hours inorder to catch </em><em>you.</em>
<em>(</em><em>b)</em><em> </em><em>You </em><em>both </em><em>will </em><em>be </em><em>6</em><em>7</em><em>5</em><em> </em><em>miles</em> <em>away </em><em>from </em><em>Ellensburg</em><em> </em><em>at </em><em>that </em><em>time.</em>
If you leave at 1 pm; At 2:30pm;
- That is; 1 and a half hours after leaving; you must have covered a distance, d = 75 × 1.5
- d = 112.5miles.
Therefore, your position; S after 2:30pm is given by;
S(a) = 75t + 112.5 miles from Ellensburg.
For your friend; travelling at 90miles/hr;
- His position is given as; S(b) = 90 × t
(a) For your friend to catch you, you both must be in the same position;
75t + 112.5 = 90t
90t -75t = 112.5
t = 112.5/15
t = 7.5hours
(b) To determine how far you both are from Ellensburg; we can either evaluate:
S(b) = 90t or S(a) = 75t + 112.5
Therefore, By evaluating S(b) = 90t.
S(b) = 90 × 7.5
S(b) = 675miles from Ellensburg.
Read more:
brainly.com/question/24234606
<span>At the top of a ramp, all of the energy of the car is potential: that is, it has yet to be moved but has the ability to move. As the car is sliding down the ramp, the potential energy is being transformed into kinetic energy, which reaches a maximum at halfway down the ramp. After this point, the kinetic energy begins to lessen and the potential energy begins to increase, until the car comes to a full stop, at which point kinetic energy is at zero and the potential energy is again at a maximum.</span>
The answer would be f(5)=5x+15 I think.
