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Marianna [84]
3 years ago
5

sara and tory are out fishing on the lake on a hot summer day when they both decide to go for a swim. sara dives off the front o

f the boat with a force of 45° N, while Tory dives off the back of the boat with a force of 60° N. Draw a vector diagram of the situation. Find the resultant force on the boat.

Physics
1 answer:
crimeas [40]3 years ago
3 0

Here it is an application of Newton's III law

as we know by Newton's III law that every action has equal and opposite reaction

So here as we know that two boys jumps off the boat with different forces

from front side of the boat the boy jumps off with force 45 N which means as per Newton's III law if boy has a force of 45 N in forward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 45 N

Now similar way we can say

from back side of the boat the boy jumps off with force 60 N which means as per Newton's III law if boy has a force of 60 N in backward direction then he must apply a reaction force on the boat in reverse direction of same magnitude

So boat must have an opposite force on front end with magnitude 60 N

So here net force due to both jump on the boat is given by

F_{net} = F_1 - F_2

F_{net} = 60 - 45

F_{net} = 15 N

so boat will have net force F = 15 N in forward direction due to both jumps

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Help!!! I need it today <br> Thank you in advance
svlad2 [7]

Answer:

 F = - k (x-xo) a graph of the weight or applied force against the elongation obtaining a line already proves Hooke's law.

Explanation:

The student wants to prove hooke's law which has the form

          F = - k (x-xo)

To do this we hang the spring in a vertical position and mark the equilibrium position on a tape measure, to simplify the calculations we can make this point zero by placing our reference system in this position.

Now for a series of known masses let's get them one by one and measure the spring elongation, building a table of weight vs elongation,

we must be careful when hanging the weights so as not to create oscillations in the spring

we look for the mass of each weight

         W = mg

          m = W / g

and we write them in a new column, we make a graph of the weight or applied force against the elongation and it should give a straight line; the slope of this line is sought, which is the spring constant.

The fact of obtaining a line already proves Hooke's law.

5 0
3 years ago
An object is 1.0 cm tall and its erect image is 5.0 cm tall. what is the exact magnification?
ikadub [295]
The exact magnification of the objects is calculated by dividing the cinema. We calculate it by diving the erect image size by the object size. From the given above, we find the exact magnification by dividing 5.0 cm by 1.0 cm. Thus, the answer would be 5. 
7 0
3 years ago
The gravitational force between two objects is 100 N.
defon
200N is the answer (at least thats what I think)
5 0
3 years ago
Will increasing length and cross-sectional area increase the resistance of an object?
Klio2033 [76]

Answer:

Increasing length increases resistance

increasing cross sectional area reduces the resistance

.

Explanation:

The formula for resistance of an object is

r = d \frac{l}{a}

where r is resistance, d is resistivity of the material, l is length of material and a is cross sectional area of the object. This equation shows us that resistance is directly proportional to length and inversely proportional to cross sectional area. Hence, increasing length increases resistance while increasing cross sectional area reduces the resistance.

If these 2 variables are varied to the same extent, the net effect can be zero on the resistance.

5 0
3 years ago
The energy required to dislodge electrons from cesium metal via the photoelectric effect is 207 kJ/mol . What wavelength (in nm)
ki77a [65]

Answer:

So wavelength in nm will be \lambda =0.956\times 10^{-19}nm    

Explanation:

We have given that the energy = 207 KJ/mol =207\times 10^3j/mol

Speed of light c=3\times 10^8m/sec

Plank's constant h=6.6\times 10^{-34}J-s

According to plank's rule energy of the photon is given by

E=\frac{hc}{\lambda }

207\times 10^3=\frac{6.6\times 10^{-34}\times 3\times 10^8}{\lambda }

\lambda =0.956\times 10^{-28}m

So wavelength in nm will be \lambda =0.956\times 10^{-19}nm

6 0
3 years ago
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