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Naddik [55]
3 years ago
9

A light plane must reach a speed of 33m/s for takeoff.how long a runway is needed if the the acceleration is 3.0m/s^2

Physics
1 answer:
Tanzania [10]3 years ago
8 0

Remark

Always write down your givens and what you want to find. The formula you use for such questions will suggest itself if you do this.

Givens

a = 3.0 m/s^2

vi = 0  I presume that's that the question assumes.

vf = 33 m/s

You want d

Formula

vf^2 = vi^2 + 2*a*d

Solution

33^2 = 0^2 + 2 * 3 * d

1089 = 6*d

d = 1089/6

d = 181.5 meters

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Answer:

the two vehicles will be moving at a speed of 6.16  m/s

Explanation:

This is a case of completely inelastic collision, therefore, the conservation of momentum can be written as:

m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f

which given the information provided results into:

m_1\,v_1+m_2\,v_2=(m_1+m_2)\,v_f\\(1250)\,(0)+(3550)\,(8.33)=(1250+3550)\,v_f\\29571.5=4800\,v_f\\v_f=6.16\,\,m/s

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3 years ago
The bonds that hold water molecules together are due to shared electrons and known as
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Answer: The bond that hold water molecules together are due to shared electrons. The bond of shared electrons is known as a covalent bond.

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What causes a objects to move or stay still? claim and evidence
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A spherical Christmas tree ornament is 8.00 cm in diameter. What is the magnification of an object placed 12.0 cm away from the
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The magnification of the ornament is 0.25

To calculate the magnification of the ornament, first, we need to find the image distance.

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  • 1/f = u⁻¹+v⁻¹.................... Equation 1

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  • u = image distance
  • v = object distance.

make u the subject of the equation

  • u = fv/(f+v)................ Equation 2

From the question,

Given:

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Substitute these values into equation 2

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Hence, The magnification of the ornament is 0.25

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