Answer:
 the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
Explanation:
Pitot tube 

U = velocity(m/s)
= stagnation pressure (pa)
= static pressure (pa)
d = fluid density(kg/m³)

v = true velocity
= 101325 + 1/2(1.225)(25)²


d = 1.225kg/m³

 the airspeed indicated by the pitot-tube driven airspeed indicator is 91.23m/s
 
        
             
        
        
        
Answer: the maximum heigth of the stadium at ist back wall is 151.32 ft
Explanation:
1. use the position (x) equation in parobolic movement to find the time (t)
565 ft = [frac{176 ft}{1 s\\}[/tex] * cos (35°)  * t
t= 3.92 s
2. use the position (y) equation in parabolic movement to find de maximun heigth  the ball reaches at 565 ft from the home plate.
y= [[frac{176 ft}{1 s\\}[/tex] * sen (35°) * 3.92 s] - 
y= 148.32 ft 
3. finally add the 3 ft that exist between the home plate and the ball
148.32 ft + 3 ft = 151.32
 
        
             
        
        
        
3750 seconds to travel that far