Radical form for 112 would be 4{7 and then I think you can just search up how to reduce the 4 to 7 i don’t have the symbol btw
Answer:
sorry im on a time lapse, so the answer is 2 1/2. hope it helps
Step-by-step explanation:
Answer:
- The two solutions are:

- The next and every step are below.
Explanation:
1.
: Given (addition property / add - 3 to both sides)
2.
: Given (commom factor - 2)
3. 
To obtain the perfect square it was added the square of half of the coefficient of x: (1/2)² = 1/4, inside the parenthesis.
Since, the terms inside the parentthesis are multiplied by - 2, you have to add - 2 (1/4) = - 1/2 to the left side of the equation.
4. Now, you have that the trinomial x² - x + 1/4 is a square perfect trinomial which is factored as (x - 1/2)² and get the expression:

5. Divide both sides by - 2 to get the next expression:

6. The last step is to extract squere root from both sides of the equality:

Hello, the answer is x=-1/2
Here are the steps....
<span><span><span><span><span>−<span>7x</span></span>+12</span>+</span>−<span>2x</span></span>=<span>23+<span>13x</span></span></span><span><span><span>(<span><span>−<span>7x</span></span>+<span>−<span>2x</span></span></span>)</span>+<span>(12)</span></span>=<span><span>13x</span>+23</span></span>(Combine Like Terms)<span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+23</span></span><span><span><span>−<span>9x</span></span>+12</span>=<span><span>13x</span>+<span>23
</span></span></span><span><span><span><span>−<span>9x</span></span>+12</span>−<span>13x</span></span>=<span><span><span>13x</span>+23</span>−<span>13x</span></span></span><span><span><span>−<span>22x</span></span>+12</span>=<span>23
</span></span><span><span><span><span>−<span>22x</span></span>+12</span>−12</span>=<span>23−12</span></span><span><span>−<span>22x</span></span>=<span>11
</span></span><span><span>−<span>22x</span></span><span>−22</span></span>=<span><span><span>11<span>−22</span></span></span></span><span>x=<span><span><span>−1</span>2</span></span></span><span>
</span>Hope this helps you!!