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elena55 [62]
3 years ago
5

Simplify the radical expression: 2√3(5√2 - 4√5)

Mathematics
1 answer:
OleMash [197]3 years ago
5 0
The answer is: 10√6−8√15
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If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
kupik [55]
<span>If i started a business making braclets for $2 and necklaces for $3 with a budget >200 what would be the inequality equation?
How would I graph

Solution:
let x= number of bracelets
    y= number of necklaces

Thus, the equation would be:
</span>$2x+$3y>200

In graphing this equation, you just have to substitute any number for the values of x and y as long as when substituted, their sum is greater than 200
8 0
3 years ago
How do you solve 7a- 17=4a+1
Dennis_Churaev [7]

Answer:

a = 6

Explanation:

7a − 17 = 4a + 1

Subtract 4a from both sides

7a − 17 − 4a = 4a + 1 − 4a

3a − 17 = 1

Add 17 to both sides

3a − 17 + 17 = 1 + 17

3a = 18

Divide both sides by 3

3a / 3 = 18 / 3

a = 6

5 0
3 years ago
In 0.73, in which place is the 0
Svetllana [295]

Answer:

The digit '0' is in the ones place.

6 0
2 years ago
Read 2 more answers
A lathe is set to cut bars of steel into lengths of 6 cm. The lathe is considered to be in perfect adjustment if the average len
Gnom [1K]

Answer:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

df=n-1=93-1=92  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

Step-by-step explanation:

Information provided

\bar X=5.97 represent the sample mean for the length

s=0.4 represent the sample standard deviation

n=93 sample size  

\mu_o =6 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic  

p_v represent the p value for the test

System of hypothesis

We need to conduct a hypothesis in order to check if the lathe is in perfect adjustment (6cm), then the system of hypothesis would be:  

Null hypothesis:\mu = 6  

Alternative hypothesis:\mu \neq 6  

since we don't know the population deviation the statistic is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing in formula (1) we got:

t=\frac{5.97-6}{\frac{0.4}{\sqrt{93}}}=-0.723    

E. -0.723

P value

The degrees of freedom are given by:

df=n-1=93-1=92  

Since is a two tailed test the p value would be:  

p_v =2*P(t_{(92)}  

Since the p value is very high we don't have enough evidence to conclude that the true mean for the lengths is different from 6 cm.

5 0
3 years ago
PLZ HELP ASAP.....Your dad is researching landscaping companies to come put new mulch out for the year. The first company charge
Blizzard [7]

Answer: After 5 bags of mulch, the cost for both companies will be the same.

Step-by-step explanation:

The cost for Company can be represented by the equation: y= 10m+100

The cost for Company B can be represented by the equation: y= 30m

To find the amount of mulch, their cost needs to be the same, I will solve for m

10m+100=30m

-10m 10m

100=20m

Divide both side by 20

100/20=20m/20

5=m or m=5

So after 5 bags of mulch, the total cost for both companies is the same.

6 0
3 years ago
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