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Anarel [89]
3 years ago
12

Use the given conditions to write an equation for the line in point-slope form and general form.

Mathematics
1 answer:
Tatiana [17]3 years ago
5 0

Answer:

y=4/7 x +99/7 general form

y2-y1=m(x2-x1) =y2-9=4/7(x-(-9)

Step-by-step explanation:

4x - 7y - 2

slope=4/7 and b=-2/7

y=4/7 x-2/7

the slopes of parallel lines are equal. Note that two lines are parallel if their slopes are equal and they have different y-intercepts

point slope form : y2-y1=m(x2-x1) =y2-9=m(x-(-9)

y-9=4/7(x+9)

y=4/7x+36/7+9

y=4/7 x +99/7 general form

I hope it works

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Please find the question
melisa1 [442]

Answer:

By distance formula ,

AB² = (5+1)² + (3-6)²

AB² = 36 + 9

AB = 6.71 units

6 0
3 years ago
Help me to do this question ​
zysi [14]

Answer:

c1) adjacent

c2) not adjacent

c3) adjacent

c4) not adjacent

c5) adjacent

c6) not adjacent

d1) 20°

Complement: 90° - 20° = 80°

Supplement: 180° - 20° = 160°

d2) 77°

Complement: 90° - 77° = 13°

Supplement: 180° - 77° = 103°

d3) 101°

Complement: doesn't have a complement.

Supplement: 180° - 101° = 79°

d4) 90°

Complement: 90° - 90° = 0°

Supplement: 180° - 90° = 90°

d5) 96°

Complement: doesn't have a complement

Supplement: 180° - 96° = 84°

d6) x

Complement: 90° - x

Supplement: 180° - x

d7) y

Complement: 90° - y

Supplement: 180° - y

7 0
3 years ago
For the polynomial below, -2 is a zero.
Harlamova29_29 [7]

Answer:

Step-by-step explanation:

please note -2 is not a zero ,it should be 2 is a zero.

by synthetic division

2|  1  4 -10 -4

  |      2  12  4

  |----------------

     1  6   2  | 0

x²+6x+2=0

x=\frac{-6 \pm \sqrt{36-8} }{2} \\or~x=\frac{-6 \pm2\sqrt{7} }{2} \\or ~x=-3\pm \sqrt{7} \\h(x)=(x-2)(x^2+6x+2)=(x-2)(x-3+\sqrt{7} )(x-3-\sqrt{7})

7 0
3 years ago
What is the equation of the line that passes through (4,3) and (-4,-1)?
german
\bf \begin{array}{ccccccccc}
&&x_1&&y_1&&x_2&&y_2\\
%  (a,b)
&&(~ 4 &,& 3~) 
%  (c,d)
&&(~ -4 &,& -1~)
\end{array}
\\\\\\
% slope  = m
slope =  m\implies 
\cfrac{\stackrel{rise}{ y_2- y_1}}{\stackrel{run}{ x_2- x_1}}\implies \cfrac{-1-3}{-4-4}\implies \cfrac{-4}{-8}\implies \cfrac{1}{2}
\\\\\\
% point-slope intercept
\stackrel{\textit{point-slope form}}{y- y_1= m(x- x_1)}\implies y-3=\cfrac{1}{2}(x-4)
\\\\\\
y-3=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x+1
6 0
3 years ago
What is the slope of the line that passes through the pair of points? (1, 7), (10, 1)
Harrizon [31]
I believe it would be C<span />
4 0
4 years ago
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