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3 years ago

The abdominopelvic region that is bordered by all four imaginary lines is the

Mathematics

1 answer:

Ainat [17]3 years ago

4 0

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

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A new security system needs to be evaluated in the airport. The probability of a person being a security hazard is 4%. At the ch

ivolga24 [154]

Answer:

(a) 0.9412

(b) 0.9996 ≈ 1

Step-by-step explanation:

Denote the events a follows:

$P$ = a person passes the security system

$H$ = a person is a security hazard

Given:

$P (H) = 0.04,\ P(P^{c}|H^{c})=0.02\ and\ P(P|H)=0.01$

Then,

$P(H^{c})=1-P(H)=1-0.04=0.96\\P(P|H^{c})=1-P(P|H)=1-0.02=0.98\\$

(a)

Compute the probability that a person passes the security system using the total probability rule as follows:

The total probability rule states that: $P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The value of P (P) is:

$P(P)=P(P|H)P(H)+P(P|H^{c})P(H^{c})\\=(0.01\times0.04)+(0.98\times0.96)\\=0.9412$

Thus, the probability that a person passes the security system is 0.9412.

(b)

Compute the probability that a person who passes through the system is without any security problems as follows:

$P(H^{c}|P)=\frac{P(P|H^{c})P(H^{c})}{P(P)} \\=\frac{0.98\times0.96}{0.9412} \\=0.9996\\\approx1$

Thus, the probability that a person who passes through the system is without any security problems is approximately 1.

7 0

3 years ago

A movie theater complex gave a poll as viewers exited from two theaters showing the same film. They had a 20% response rate from

sp2606 [1]

Answer:

Let´s define the variables:

x = number of people in theater A

y = number of people in theater B

We know that a 20% (or 0.2 in decimal form) of the people in theater A answered the survey, then the number of people from theater A that answered the survey is: Na = 0.2*x

We know that a 30% (or 0.3 in decimal form) of the people in theater B answered the survey, then the number of people from theater B that answered the survey is: Nb = 0.3*y

There where 800 people in total (counting from the two theatres)

Then x + y = 800.

A) In this case we have:

Na = Nb

this means that:

0.2*x = 0.3*y

and we also have the equation:

x + y = 800

To solve this, we need to isolate one variable in one of the equations, i will isolate x in the second equation:

x = 800 - y

And now we can replace this in the other equation to get:

0.2*(800 - y) = 0.3*y

We need to solve this for y:

160 - 0.2*y = 0.3*y

160 = 0.3*y + 0.2*y = 0.5*y

160/0.5 = y = 320

Then there where 320 people in theater B, and:

x + y = 800

x + 320 = 800

x = 800 - 320 = 480

There where 480 people in theather A.

B) Now we have:

x = 440

y = 360

then:

Na = 0.2*440 = 88

In theater A, 88 people answered the survey.

Nb = 0.3*360 = 108

In theater B, 108 people answered the survey.

In total, 88 + 108 = 196 people answered the survey.

5 0

3 years ago

Help please.................

olganol [36]

Answer:

(-4, 0) and (5/2, 0)

Step-by-step explanation:

if you graph the equation you can see where the curve intersects the x-axis or you can factor the equation into: (2x - 5)(x + 4) = 0

set each factor equal to zero and solve:

2x - 5 = 0

2x = 5

x = 5/2

x + 4 = 0

x = -4

6 0

2 years ago

Tameka bought 50 cans of soda ( cola, grape, and orange) to serve at a party. She has 8 more colas than grape sodas, and 3 less

Gwar [14]

Answer:

Orange = 12

Grape = 15

Cola = 23

Step-by-step explanation:

Turning this into equations you can give each soda a variable

Cola = C | Grape = G | Orange = R

Then you get:

8 + G = C

R + 3 = G

C + G + R = 50

We want to get a variable all by itself in an equation so first I'm going to put the second equation (R + 3 = G) in the first (8 + G = C) by replacing the G to get

8 + (R + 3) = C Combine the variables 11 + R = C and put that new equation into the last equation

(11 + R) + G + R = 50

Now plug our original second equation (R + 3 = G) into our third to get

(11 + R) + (R + 3) + R = 50

Combine and get

14 + 3R = 50 Subtract over the 14

3R = 36 Divide by 3

Orange Sodas = 12

Our new 3rd Equation is now: C + G + 12 = 50, subtract over 12 to get

C + G = 38

Plug either equation 1 or 2 into that one, I'll do 1

(8 + G) + G = 38

8 + 2G = 38

2G = 30

Grape Sodas = 15

Now our 3rd equation is C + 15 = 38, subtract over 15

Cola Sodas = 23

Orange = 12

Grape = 15

Cola = 23

12 + 15 + 23 = 50

7 0

3 years ago

A cup, when full, contains 3/10 litres of

AnnyKZ [126]

Answer:

The answer is 30. 9 divided by 0.3 is 30.

6 0

3 years ago