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xz_007 [3.2K]
3 years ago
7

The abdominopelvic region that is bordered by all four imaginary lines is the

Mathematics
1 answer:
Ainat [17]3 years ago
4 0

Umbilical point.

An umbilic point, likewise called just an umbilic, is a point on a surface at which the arch is the same toward any path.

 

In the differential geometry of surfaces in three measurements, umbilics or umbilical focuses are focuses on a surface that are locally round. At such focuses the ordinary ebbs and flows every which way are equivalent, consequently, both primary ebbs and flows are equivalent, and each digression vector is a chief heading. The name "umbilic" originates from the Latin umbilicus - navel.

 

<span>Umbilic focuses for the most part happen as confined focuses in the circular area of the surface; that is, the place the Gaussian ebb and flow is sure. For surfaces with family 0, e.g. an ellipsoid, there must be no less than four umbilics, an outcome of the Poincaré–Hopf hypothesis. An ellipsoid of unrest has just two umbilics.</span>

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3/2 x 1/4 x 5/3 = v.
jekas [21]

Answer: 5/8 or 0.625

Step-by-step explanation:

3/2x1/4= 3/8

Then, 3/8x5/3= 15/24

15/24 simplified equals 5/8. 5/8 in decimal form is 0.625

3 0
2 years ago
What is the perimeter of this equilateral triangle?
bonufazy [111]

9 + 9 + 9

27

your welcome


5 0
2 years ago
Read 2 more answers
8. H={all numbers of the form 3n+1, for n a natural number} under multiplication?
poizon [28]

Answer and Step-by-step explanation:

H= {all numbers of the form 3n+1, for n natural number} under multiplication:

Sol: all number of the form 3n+1, for n natural number so, put n=2, 3(2) +1 = 7, which is a natural number. A natural number under multiplication does not form a group because its inverse does not exist.

J= {all number of the form 3n+2, for n natural number} under multiplication:

Sol: all the number of the form 3n+2, n is the natural number does not form a group under multiplication because the identity element does not form in this set, and inverse does not exist.

K= {perfect squares of integers} under addition:

Sol: perfect square of integers under addition does not form a group because the inverse does not exist. For example, for any element x, inverse (-x) does not exist because of a square integer.

L= {perfect squares of integers} under multiplication:

Sol: a set of the perfect square of integers under multiplication is not a set, because it does not have the inverse property

M= {all numbers of the form 2, for n natural number} under addition:

Sol: natural number in the form of 2n, n is a natural number under addition is not a group as it does not have identity property. Identity property, under addition, is zero.

N= {all number of the form 2n, n is natural number} under multiplication:

All number of the form 2n, n is the natural number under multiplication is not a group. Because its inverse does not exist. For example, an element x belongs to a natural number; its inverse (1/x) does not exist in this set.

8 0
2 years ago
in one year dog's weigh from 64 pounds to 80 pounds . by what percentage did the dog's weght increase
Masja [62]

Answer:

15%

Step-by-step explanation:

First, let's find how many pounds the dog's weight increased by during the year.

80 - 64 = 16

Now, knowing that the dog's weight increased by 16 pounds, we can use that to figure out the percentage of 16 out of 64 (divide them, then multiply by 100 to get a percentage).

\frac{16}{64} • 100 = 0.25 • 100 = 25%

8 0
2 years ago
10. Allen has $3.30 in dimes and quarters. If he has 24 coins in all, find the number of dimes and quarters
agasfer [191]

Answer:

6 Quarters and 18 Dimes

Step-by-step explanation:

18 x 0.10 = $1.8

6 x 0.25 = $1.5

$1.5 + $1.8 = $3.30

3 0
2 years ago
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