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2 years ago

the area of a rectangular field is x^2-x-72 m^2. The length of the field is x+8 cm. What is the width of the field meters.

1 answer:

5 0

Hello,

A(x)=x²-x-72 (m²)
L=(x+8) (cm)= (x+8)/100 (m)

We suppose here x≠-8
(in reality x²-x-72>0 ==>x<-8 or x>9
but x+8>0 ==> x>-8
then
only x>9 are solutions)

W=A(x)/ ((x+8)/100 )=100*(x²-x-72)/(x+8)= 100*(x-9)(x+8)/(x+8)=100*(x-9)

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3 years ago

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Nana76 [90]

Answer:

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3 years ago

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ioda

True.

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2 years ago

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Shtirlitz [24]

Answer:

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⭐ Answered by Kakashi ʕ •㉨• ʔ⭐

⭐ Brainliest would be appreciated!⭐

⭐ If you have questions, leave a comment, I'm happy to help! ⭐

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2 years ago

Read 2 more answers

If there are 16 ounces in a pound how manyh are in 24 ounces

iren2701 [21]

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3 years ago