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denis-greek [22]
3 years ago
15

Asap!! 85=2x(x^2+3)(2x+5) use quadratic equation

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

85=2x(x^2+3)(2x+5)

85=2x(2x^3+5x^2+6x+15)

85=4x^4+10x^3+12x^2+30x

4x^4+10x^3+12x^2+30x-85=0

2x^2(2x^2+5x+6)+30x-85=0

shoot, this isn't possible with quadratic, maybe you can get somewhere from here

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Please answer I have a freaking e in my math class​
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Answer: I would answer but the image is blocked for me- can you type the problem by any chance?

Step-by-step explanation:

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3 years ago
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And? It’s there a full question?
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3 years ago
Which equation demonstrates the additive identity property?
Mrrafil [7]

Answer:

Step-by-step explanation:

Solve for o in the equation (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 41o(7 + 4)(1) = 7 + 41o(7 + 41) + ( - 7 - 41) = 0

We first need to simplify the expression removing parentheses

Simplify 41o(7 + 4): Distribute the 41o to each term in (7+4)

41o * 7 = (41 * 7)o = 287o 41o * 4 = (41 * 4)o = 164o

Our Total expanded term is 287o + 164o

Simplify 41o(7 + 41): Distribute the 41o to each term in (7+41)

41o * 7 = (41 * 7)o = 287o 41o * 41 = (41 * 41)o = 1681o

Our Total expanded term is 287o + 1681o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o(1) = 7 + 287o + 1681o + ( - 7 - 41) = 0

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Simplify 164o(1): Distribute the 164o to each term in (1)

164o * 1 = (164 * 1)o = 164o Our Total expanded term is 164o

Our updated term to work with is (7 + 4) + (7 - 41) = 14©(7 + 4) + 0 = 7 + 287o + 164o = 7 + 287o + 1681o + ( - 7 - 41) = 0

Step 1: Group variables: We need to group our variables (7 and 14©(7. To do that, we subtract 14©(7 from both sides (7 - 14©(7 = 14©(7 - 14©(7

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5 0
3 years ago
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Answer:

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The total price of Alyssa's meal is $22.68.

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