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denis-greek [22]
3 years ago
15

Asap!! 85=2x(x^2+3)(2x+5) use quadratic equation

Mathematics
1 answer:
emmainna [20.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

85=2x(x^2+3)(2x+5)

85=2x(2x^3+5x^2+6x+15)

85=4x^4+10x^3+12x^2+30x

4x^4+10x^3+12x^2+30x-85=0

2x^2(2x^2+5x+6)+30x-85=0

shoot, this isn't possible with quadratic, maybe you can get somewhere from here

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3 years ago
Need to know the population in 2015
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\bf P=1110.9e^{kt}\quad 
\begin{cases}
P=1200 &\textit{in thousands}\\
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\end{cases}\implies 1200=1110.9e^{k2}
\\\\\\
\cfrac{1200}{1110.9}=e^{2k}\implies ln\left( \frac{1200}{1110.9} \right)=ln(e^{2k})\implies ln\left( \frac{1200}{1110.9} \right)=2k
\\\\\\
\cfrac{ln\left( \frac{1200}{1110.9} \right)}{2}=k\implies 0.0385755\approx k\implies 0.0386\approx k\\\\
-------------------------------\\\\

\bf P=1110.9e^{0.0386t}\qquad 
\begin{cases}
t=14\\
\textit{year 2015}
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\\\\\\
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2 years ago
(x^2-2)^2-10(x^2-2)+21=0 find one value of x that is a solution to the equation
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