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sp2606 [1]
3 years ago
15

The population of deer in a given park is modeled by y = d(x) = A( 1 2 )x + B, where x is the elapsed time in years since 2019.

According to the model, which is the best prediction of the number of deer in the park in 2099?
A) A

B) B

C) A + B

D) A − B
Mathematics
2 answers:
kirill [66]3 years ago
8 0

Answer:

Step-by-step explanation:

The answer is B) B :)

Cerrena [4.2K]3 years ago
6 0

Answer:

The answer is B

Step-by-step explanation:

According to USA Test prep it says so, but i didn't quite get the explanation so bear with me. Thank you :)(:

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On the map of a town, 1 cm represents 6 miles. Find the distance represented by 4.5 cm
Daniel [21]

Answer:

27 miles

Step-by-step explanation:

1cm is 6 miles,

4.5cm is ?miles

?=6*4.5/1=27

6 0
3 years ago
What is -8 square root of 9 when simplified​
gregori [183]

Answer:

\large\boxed{-8\sqrt9=-24}

Step-by-step explanation:

\sqrt{a}=b\iff b^2=a\\\\\sqrt9=3\ \text{because}\ 3^2=9\\\\-8\sqrt9=-8(3)=-24

7 0
3 years ago
A study conducted to determine the relationship between the age, x, in years of a certain brand of motorcycle and its value, y,
kirza4 [7]

Based on the equation, y = -750·x + 8500, the estimated value of a

motorcycle that is 5 years old is <u>$4,750</u>.

<h3>How can the given equation help to estimate the value of the motorcycle?</h3>

The regression equation that models the data is; y = -750·x + 8500

Where;

y = The value of the brand of motorcycle in dollars

x = The age of the motorcycle

When the motorcycle is 5 years old, we have;

x = 5

y = -750 × 5 + 8500 = 4750

Based on the equation, the estimated value of a motorcycle that is 5 years old, y =<u> $4,750</u>

Learn more equations here:

brainly.com/question/20475360

4 0
2 years ago
Which expression is a difference of two terms that is equivalent to 6z - 13
Ivan

Answer:7 that’s easy

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find x. Show all work. I got 52.5 not sure if it’s right
Firdavs [7]
I think you’re right with 52.5
3 0
3 years ago
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