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OLga [1]
3 years ago
14

Help!! Solve for v. 14v - 10 = 14v

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

sln

14v-10=14v

14v-14v=10

the Value of v don't get because when 14v-14v is equal to zero

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Match the function with its graph. a. 1C, 2B, 3D, 4A c. 1D, 2A, 3C, 4B b. 1A, 2D, 3B, 4C d. 1A, 2B, 3C, 4D Please select the bes
oksano4ka [1.4K]

Answer:

The correct answer is "Option C".

Step-by-step explanation:

Given:

\bold{ 1) y= -\tan (x- \frac{\pi}{2})}\\\\\bold{ 2) y= \tan (x+ \frac{\pi}{2})}\\\\\bold{ 3) y= -\cot (x- \frac{\pi}{2})}\\\\\bold{ 4) y= \cot (x+ \frac{\pi}{2})}\\\\

solve the above equation:

\Rightarrow 1) \ y= -\tan (x- \frac{\pi}{2})\\\\\Rightarrow \ y= \tan (\frac{\pi}{2}-x)\\\\\Rightarrow \ y= \cot x \ \ \ \ \ \bold{ that \ matchs \ graph \ D}\\\\ \Rightarrow 2) \ y= \tan (x+ \frac{\pi}{2})\\\\\Rightarrow \ y= - \cot x \ \ \ \ \bold{ that \ matchs \ graph \ A}\\\\

\Rightarrow 3) \ y= -\cot (x- \frac{\pi}{2})\\\\\Rightarrow \ y=\cot ( \frac{\pi}{2}-x)\\\\\Rightarrow \ y=\tan  x\ \ \ \ \bold{that \ matchs \ graph \ C}\\\\

\Rightarrow 4) \ y= \cot (x+ \frac{\pi}{2})\\\\\Rightarrow  \ y= \cot (\frac{\pi}{2}+x)\\\\\Rightarrow  \ y= \ -tan x \ \ \ \ \  \bold{ that \ matchs \ graph \ A}

The final answer is "Option C".

8 0
3 years ago
Which choice is equivalent to the expression below when y2 0?<br> √y^2 + √16y^3 – 4y√y
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Answer:

Option C.

Step-by-step explanation:

We start with the expression:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

where y > 0. (this allow us to have y inside a square root, so we don't mess with complex numbers)

We want to find the equivalent expression to this one.

Here, we can do the next two simplifications:

\sqrt{16*y^3} = \sqrt{16} \sqrt{y^3} = 4*\sqrt{y^3}

And:

y*\sqrt{y} = \sqrt{y^2} *\sqrt{y} = \sqrt{y^2*y} = \sqrt{y^3}

If we apply these two to our initial expression, we can rewrite it as:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y}

\sqrt{y^3}  + 4*\sqrt{y^3} - 4\sqrt{y^3} = \sqrt{y^3}

Here we can use the second simplification again, to rewrite:

\sqrt{y^3} = y*\sqrt{y}

So, concluding, we have:

\sqrt{y^3}  + \sqrt{16*y^3} - 4*y\sqrt{y} = y*\sqrt{y}

Then the correct option is C.

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Answer:

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Step-by-step explanation:

its a crown by report

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