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OLga [1]
3 years ago
14

Help!! Solve for v. 14v - 10 = 14v

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

sln

14v-10=14v

14v-14v=10

the Value of v don't get because when 14v-14v is equal to zero

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What is the domain and range of the following function
mel-nik [20]

Answer:

domain: (–∞,∞)    or  all real numbers

range: (–∞,∞)       or  all real numbers

Step-by-step explanation:

domain is left to right (x-axis). looking at the graph, as you go from left to right, the x-values are infinitely getting more negative and positive.

range is bottom to top (y-axis). as you go from bottom to top, the y-values are infinitely getting more negative and positive.

6 0
3 years ago
a rectangular frame has a length of 3 and 1/8 feet and an area of 2 and 3/4 feet.what is the width,w, feet,of the fame? please a
Galina-37 [17]
If you would like to find the width of the frame in feet, you can do this using the following steps:

length * width = area
3 1/8 feet * width = 2 3/4 square feet
25/8 feet * width = 11/4 square feet
25/8 * width = 11/4
width = 11/4 / 25/8
width = 11/4 * 8/25
width = 22/25 = 0.88 feet

The correct result would be 22/25 feet.
5 0
3 years ago
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Graph: y = 12 - 41 + 2
tankabanditka [31]

Step-by-step explanation:

y=-27

...................

3 0
3 years ago
Please help me find the area of this shape please!
wolverine [178]
I’m pretty sure it’s just 28
8 0
3 years ago
In isosceles $\triangle abc$ (with $ab = ac$), point $d$ lies on $ab$ such that $cd = cb$. if $\angle adc = 115^\circ$, what is
Nuetrik [128]

1. Angles ADC and CDB are supplementary, thus

m∠ADC+m∠CDB=180°.

Since m∠ADC=115°, you have that m∠CDB=180°-115°=65°.

2. Triangle BCD is isosceles triangle, because it has two congruent sides CB and CD. The base of this triangle is segment BD. Angles that are adjacent to the base of isosceles triangle are congruent, then

m∠CDB=m∠CBD=65°.

The sum of the measures of interior angles of triangle is 180°, therefore,

m∠CDB+m∠CBD+m∠BCD=180° and

m∠BCD=180°-65°-65°=50°.

3. Triangle ABC is isosceles, with base BC. Then

m∠ABC=m∠ACB.

From the previous you have that m∠ABC=65° (angle ABC is exactly angle CBD). So

m∠ACB=65°.

4. Angles BCD and DCA together form angle ACB. This gives you

m∠ACB=m∠ACD+m∠BCD,

m∠ACD=65°-50°=15°.

Answer: 15°.

3 0
3 years ago
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