Just Note the below follow the below principle
- It stands for Smaller cation and larger anion.
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Answer:
moles O₂ needed = 0.19 mole
Explanation:
4Fe(s) + 3O₂(g) => 2Fe₂O₃(s)
1.396g Fe(s) = 1.396g/56g/mol = 0.025 mole Fe(s)
0.025 mole Fe(s) reacts with 3/4(0.025 mole O₂(g) = 0.019 mole O₂(g)
Ca=40g
P=31g
Ca3=120g
P2=62g
Ca3P2=182g
Ca3/Ca3p2=120/182=0.6593=approximately 65.93%
Mass=density·volume. The density is 2.70g/mL and the volume is 353mL. So you would multiply 2.70g/mL by 353mL which will give you 953.1g. Hope that helps :)
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