Question

What is the pressure in a 5.00 L tank with 49.00 grams of oxygen gas at 350 K? ___atm

Answer 1

Answer:

The right answer is "8.81 atm".

Explanation:

Given:

V = 5.00 L

Mass = 4900 g

MW = 32 g/mol

T = 350 K

Now,

Number of moles will be:

$n = \frac{Mass}{MW}$

   $=\frac{49.00}{32}$

   $=1.53125 \ mole$

By using the ideal gas equation, we get

⇒ $PV=nRT$

or,

⇒    $P=\frac{nRT}{V}$

By substituting the values, we get

           $=\frac{1.53125\times 0.0821\times 350}{5.00}$

           $=\frac{44.1}{5.00}$

           $=8.81 \ atm$