5.0g of aluminum fluoride decomposes into aluminum and oxygen. What mass of oxygen is formed?

1‑Propanol ( P⁰ 1 = 20.9 Torr at 25 ⁰C ) and 2‑propanol ( P⁰ 2 = 45.2 Torr at 25 ⁰C ) form ideal solutions in all proportions. L

anastassius [24]

Answer : The mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

Explanation : Given,

Vapor presume of 1‑Propanol $(P^o_1)$ = 20.9 torr

Vapor presume of 2‑Propanol $(P^o_2)$ = 45.2 torr

Mole fraction of 1‑Propanol $(x_1)$ = 0.540

Mole fraction of 2‑Propanol $(x_2)$ = 1-0.540 = 0.46

First we have to calculate the partial pressure of 1‑Propanol and 2‑Propanol.

$p_1=x_1\times p^o_1$

where,

$p_1$ = partial vapor pressure of 1‑Propanol

$p^o_1$ = vapor pressure of pure substance 1‑Propanol

$x_1$ = mole fraction of 1‑Propanol

$p_1=(0.540)\times (20.9torr)=11.3torr$

and,

$p_2=x_2\times p^o_2$

where,

$p_2$ = partial vapor pressure of 2‑Propanol

$p^o_2$ = vapor pressure of pure substance 2‑Propanol

$x_2$ = mole fraction of 2‑Propanol

$p_2=(0.46)\times (45.2torr)=20.8torr$

Thus, total pressure = 11.3 + 20.8 = 32.1 torr

Now we have to calculate the mole fraction of vapor phase 1‑Propanol and 2‑Propanol.

$\text{Mole fraction of 1-Propanol}=\frac{\text{Partial pressure of 1-Propanol}}{\text{Total pressure}}=\frac{11.3}{32.1}=0.352$

and,

$\text{Mole fraction of 2-Propanol}=\frac{\text{Partial pressure of 2-Propanol}}{\text{Total pressure}}=\frac{20.8}{32.1}=0.648$

Thus, the mole fraction of vapor phase 1‑Propanol and 2‑Propanol is, 0.352 and 0.648 respectively.

3 0

3 years ago

Solve the following division problem: (3.4 x 10^7)/(6.8 x 10^3) =

eduard

Answer:

5000

Explanation:

8 0

2 years ago

During unfavorable conditions, an ameba forms a.....

Sati [7]

Cyst. It's hard-walled and sturdy.

5 0

3 years ago

Why does the rate of a reaction increase when the concentration of reactants is increased?

leva [86]

If reactants eventually collide, there is an occurrence of reaction.

<span>
Therefore, when there is an increase concentration of reactant, meaning to say that there are several moles of it every unit volume. An example of this is a room having hundred of people will absolutely get higher concentration compared to a room with one individual only.

Pertaining to effective collisions, if ever there is an increase of concentration, the frequency and rate of effective collisions among reactants surges in such a way that the rate of reaction also surges. Same with passing into a room with only 1 individual compared to hundred people blind persons, you probably want to proceed to the room with several people.</span>

<span>This is the simple logic behind that scientific existence.</span>

5 0

3 years ago

Classify the two balanced equations representing two chemical reactions

Zinaida [17]

Single Replacement & Decomposition

<h3>Further explanation</h3>

Given

Two chemical reactions

1. Cl2 + 2NaBr ⇒2NaCl + Br2

2. 2NaCl ⇒2Na + Cl2

Required

Type of reaction

Solution

Equation 1 : A single replacement reaction is a chemical reaction in which one element replaces the other elements of a compound to produce new elements and compounds

General formula :

A + BC ⇒ AC + B

Equation 2 : the decomposition reaction of a compound into its constituent elements or compounds

General formula :

AB ⇒ A + B

4 0

3 years ago