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dusya [7]
2 years ago
9

Find the inverse of the matrix using elementary row operations on the augmented matrix

Mathematics
1 answer:
musickatia [10]2 years ago
5 0

The inverse of the matrix \vec A = \left[\begin{array}{cc}1&2\\3&4\end{array}\right] is represented by the matrix \vec A^{-1} = \left[\begin{array}{cc}-2&1\\\frac{3}{2} &-\frac{1}{2} \end{array}\right].

<h3>How to determine the inverse matrix</h3>

A matrix <em>A</em> has an <em>inverse</em> matrix if and only if its determinant is different than 0. Given that we have a matrix formed by 2 rows and 2 columns, we can obtain the following <em>inverse</em> matrix by using the following formula:

\vec A ^{-1} = \frac{1}{\det (\vec A)} \cdot adj (\vec A)   (1)

Where adj (\vec A) is the adjoint of the matrix, which is the transposed of the <em>cofactor</em> matrix.

If we know that \vec A = \left[\begin{array}{cc}1&2\\3&4\end{array}\right], then the inverse of the matrix is determined below:

\det (\vec A) = -2

adj (\vec A) = \left[\begin{array}{cc}4&-2\\-3&1\end{array}\right]

\vec A^{-1} = -\frac{1}{2}\cdot \left[\begin{array}{cc}4&-2\\-3&1\end{array}\right]

\vec A^{-1} = \left[\begin{array}{cc}-2&1\\\frac{3}{2} &-\frac{1}{2} \end{array}\right]

The inverse of the matrix \vec A = \left[\begin{array}{cc}1&2\\3&4\end{array}\right] is represented by the matrix \vec A^{-1} = \left[\begin{array}{cc}-2&1\\\frac{3}{2} &-\frac{1}{2} \end{array}\right]. \blacksquare

To learn more on matrices, we kindly invite to check this verified question: brainly.com/question/11367104

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In the diagram, ΔGHJ ≅ ΔSTU.
valina [46]

Answer:

m∠J = 67°

m∠T = 67°

m∠G =46°

ST = 5cm

HJ = 3.7cm

Step-by-step explanation:

Given

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  • GH = 5 cm = GJ
  • m∠GHJ = 67°

=> m∠J = 67°  ( that is the property of isosceles triangle because GH  = GJ

=>  m∠G = 180° - m∠H - m∠J =  180° - 67° - 67° = 46°

  • Because ΔGHJ ≅ ΔSTU

=> GH  = GJ = ST =SU

=> ST = 5 cm

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=> TU = HJ = 3.7 cm

=> m∠T = m∠H = 67°

So:

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ST = 5cm

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