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xeze [42]
3 years ago
9

Show that the relationship between impulse and the change in momentum is another way of stating Newton's second law of motion.

Physics
1 answer:
user100 [1]3 years ago
6 0
My answer to this question.

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In February 1955, a paratrooper fell 1200 ft from an
-Dominant- [34]

Answer:

s=1.1107\ m is the minimum depth of snow for survivable stopping.

Explanation:

Given:

  • terminal velocity of fall, u=56\ m.s^{-1}
  • mass of the paratrooper, m=85\ kg
  • force on the paratrooper by the ice to stop him, F=1.2\times 10^5\ N

<u>Firstly, we calculate the deceleration caused in the snow:</u>

a=\frac{F}{m}

a=\frac{120000}{85}

a=1411.765\ m.s^{-2}

Now, using equation of motion:

v^2=u^2+2a.s ....................(1)

where:

v = final velocity of the body after stopping

u = initial velocity of the body just before hitting the snow

a = acceleration of the body in the snow

s = distance through in the snow

Putting respective values in eq. (1)

0^2=56^2+2\times (-1411.765)\times s

s=1.1107\ m

5 0
3 years ago
Please please help. I don’t understand this.
Kazeer [188]
Which questions do you need help? I could help you
5 0
4 years ago
24 POINTS!!!!!!!!!!!!!!!
TEA [102]
Potential Energy (Initial one) = m * g * h
P.E. = 60 * 9.8 * 10
P.E. = 5880

Kinetic Energy (Final One) = 1/2 mv²
K.E. = 1/2 * 60 * (10)²
K.E. = 6000/2
K.E. = 3000

Lost Energy = 5880 - 3000 = 2880 J

In short, Your Answer would be 2880 Joules

Hope this helps!
7 0
3 years ago
Read 2 more answers
How many significant digits are in 0.3500
const2013 [10]
4 significant figures (the 0’s are considered significant because they follow a non-zero number)
7 0
4 years ago
Suppose a van de Graaff generator builds a negative static charge, and a grounded conductor is placed near enough to it so that
kozerog [31]

Given Information:

Charge = q = 7.0x10⁻⁶ C

Required Information:

Number of electrons = n = ?

Answer:

Number of electrons = 4.375x10¹³

Explanation:

We know that charge is given by

q = n*e

Where n is the number of electrons and e is the electronic charge that is 1.60x10⁻¹⁹ C

n = q/e

n = 7.0x10⁻⁶/1.60x10⁻¹⁹

n = 4.375x10¹³ electrons

Therefore, 4.375x10¹³ electrons were transferred.

4 0
3 years ago
Read 2 more answers
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