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Stels [109]
3 years ago
5

What force holds the earth-moon system together?

Physics
2 answers:
Verdich [7]3 years ago
7 0
Gravity holds the system together
valentinak56 [21]3 years ago
7 0
The force of gravity, attracting the Earth and the Moon to each other,
keeps the two bodies in orbit around their common center of mass.

(Gravity also keeps the common center of Earth-mass and Moon-mass
in orbit around the sun.)
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An alarm clock has a resistance of 14,000 ohms and is plugged into a 120-volt outlet. How much power does the clock use?
yan [13]

Power used by the clock=1.03 W

Explanation:

resistance= 14000 ohm

voltage=120 V

The formula for the power is given by

P=\frac{V^{2}}{R}

P=(120)²/14000

P=1.03 W

8 0
3 years ago
Read 2 more answers
When a red giant completes helium fusion and collapses, it becomes a ______.
Firdavs [7]
<span>When a red giang complete helium fusion and collapses, it becomes a white dwarf. The correct option is C. White dwarf are very dense stars that are usually the size of a planet. It is a stellar core reminant which mainly made up of electron degenerated matters; its mass is comparable to that of the sun while its volume is comparable to that of the earth. </span>
5 0
3 years ago
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¿cual es la velocidad de un auto que recorre 4566 metros en 4 minutos? expresar en km\h
Svetlanka [38]

Explanation:

(4566 m / 4 min) × (1 km / 1000 m) × (60 min / h) = 68.49 km/h

3 0
3 years ago
What is the bending of a wave around a barrier?
Mamont248 [21]
That's wave 'diffraction'.
3 0
3 years ago
A rod of length L and mass M has a nonuniform mass distribution. The linear mass density (mass per length) is λ=cx2, where x is
grigory [225]

Answer:

Explanation:

λ=c x²

c = λ / x²

λ is mass / length

so its dimensional formula is ML⁻¹

x is length so its dimensional formula is L

c = λ / x²

= ML⁻¹ / L²

= ML⁻³

B )

We shall find out the mass of the rod with the help of given expression of mass per unit length and equate it with given mass that is M

The mass in the rod is symmetrically distributed on both side of middle point.

we consider a small strip of rod of length dx at x distance away from middle point

its mass dm = λdx = cx² dx

By integrating it from -L to +L we can calculate mass of whole rod , that is

M = ∫cx² dx

= [c x³ / 3] from -L/2 to +L/2

= c/3 [ L³/8 + L³/8]

M = c L³/12

c = 12 M L⁻³

C ) Moment of inertia of rod

∫dmx²

= ∫λdxx²

= ∫cx²dxx²

= ∫cx⁴dx

= c x⁵ / 5 from - L/2 to L/2

= c / 5 ( L⁵/ 32 +L⁵/ 32)

= (2c / 160)L⁵

= (c / 80) L⁵

= (12 M L⁻³/80)L⁵

= 3/20 ML²

=

=

4 0
3 years ago
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