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In-s [12.5K]
3 years ago
15

A high diver dives into a swimming pool. His potential energy at the top is 10,000 J (relative to the surface of the pool). What

is his kinetic energy after diving 90% of the distance to the water?
Physics
1 answer:
Semmy [17]3 years ago
6 0

Answer:

Kinetic energy of diver at 90% of the distance to the water is 9000 J

Explanation:

Let d is the distance between the position of the diver and surface of the pool.

Initially, the diver is at rest and only have potential energy which is equal to 10000 J.

As the diver dives towards the pool, its potential energy is converting into kinetic energy due to law of conservation of energy, as total energy of the system remains same.

Energy before diving = Energy during diving

(Potential Energy + Kinetic Energy) =  (Kinetic Energy +  Potential Energy)

When the diver reaches 90% of the distance to the water, its kinetic energy

is 90% to its initial potential energy, as its initial kinetic is zero,i.e.,

K.E. = \frac{90}{100}\times10000

K.E. = 9000 J

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Two long, straight wires are separated by a distance of 32.2 cm. One wire carries a current of 2.75 A, the other carries a curre
Igoryamba

Answer:

a)\frac{F_1}{L}=1.95*10^-^5N

b)\frac{F_2}{L}=1.95*10^-^5N

Explanation:

From the question we are told that:

Distance between wires d=32.2

Wire 1 current I_1=2.75

Wire 2 current I_2=4.33

a)

Generally the equation for Force on l_1 due to I_2 is mathematically given by

F_1=I_1B_2L

Where

B_2=Magnetic field current by I_2

B_2=\frac{\mu *i_2}{2\pi d}

Therefore

F_1=I_1B_2L

F_1=I_1(\frac{\mu *i_2*l_1}{2\pi d})L

\frac{F_1}{L} =\frac{4*\pi*10^{-7}*2.75*4.33*100 }{2*\pi*12.2 }

\frac{F_1}{L}=1.95*10^-^5N

b)

Generally the equation for Force on I_2 due to I_1 is mathematically given by

F_2=I_2B_1L

Where

B_1=Magnetic field current by I_2

B_1=\frac{\mu *I_1}{2\pi d}

Therefore

\frac{F_2}{L} =I_2(\frac{\mu *I_1*I_2}{2\pi d})

\frac{F_2}{L}=1.95*10^-^5N

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3 years ago
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zavuch27 [327]

Answer:

The SI unit of power is the watt

Explanation:

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3 years ago
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A rocket is launched from a height of 3 m with an initial velocity of 15 m/s What is the maximum height of the rocket? When will
Fudgin [204]

If no extra acceleration is added to the rocket, then its velocity at time <em>t</em> is

<em>v</em> = 15 m/s - <em>g t</em>

where <em>g</em> = 9.80 m/s² is the magnitude of the acceleration due to gravity.

Also, recall that

<em>v</em>² - <em>u</em>² = 2 <em>a </em>∆<em>x</em>

where <em>u</em> is initial speed, <em>v</em> is final speed, <em>a</em> is acceleration, and ∆<em>x</em> is net displacement.

At the rocket's maximum height ∆<em>x</em>, the velocity is 0. So, the maximum height is

0² - (15 m/s)² = 2 (-<em>g</em>) ∆<em>x</em>

∆<em>x</em> = (15 m/s)² / (2 * (9.80 m/s²)) ≈ 11.48 m

But this assumes the rocket is launched from the ground. We're given that the rocket is launced from 3 m above the ground, so we need to add this to the height above. So the maximum height is closer to 14.48 m.

As mentioned before, this happens when vertical velocity is 0:

0 = 15 m/s - <em>g t</em>

<em>t</em> = (15 m/s) / (9.80 m/s²) ≈ 1.53 s

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3 years ago
Help me, what is the shape of solid?​
Naily [24]

Explanation:

Solids have a definite shape and definite volume.

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2 years ago
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A parallel-plate capacitor is made from two aluminum-foil sheets, each 5.9 cm wide and 5.6 m long. Between the sheets is a Teflo
Zarrin [17]

Answer:

1.98 x 10⁻⁷ F

Explanation:

w = width of the sheet = 5.9 cm = 0.059 m

L = length of the sheet = 5.6 m

Area of the sheet is given as

A = L w = (5.6) (0.059) = 0.3304 m²

d = distance between the sheets = 3.1 x 10⁻⁵ m

k = dielectric constant of teflon = 2.1

Capacitance is given as

C = \frac{k\epsilon _{o}A}{d}

C = \frac{(2.1)(8.85\times 10^{-12})(0.3304)}{3.1\times 10^{-5}}

C = 1.98 x 10⁻⁷ F

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