Given a square ABCD and an equilateral triangle
DPC and given a chart with which
Jim is using to prove that triangle APD is
congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate".
Answer:
20
Step-by-step explanation:
x-2y=6 and x+y=10
Multiply the second equation by 2
2x+2y = 20
Answer:
m∠2 = 140°
Step-by-step explanation:
m∠1 = m∠3, since they're vertical angles.
Solve for x:
Plug in 6 for x for either m∠1 or m∠3. Doesn't matter since they're equal.
m∠1 = (2(6) + 28)°
m∠1 = (12 + 28)°
m∠1 = 40°
Now that we know m∠1, we can now solve for m∠2.
m∠1 + m∠2 = 180°
40° + m∠2 = 180°
m∠2 = 140°
Answer:
530
Step-by-step explanation:
200+6(55)
6x55=330
200+330=530
x+3(x-5)=9 Substitute y=x-5 into every y into the first equation and solve for x
x+3x-15=9
4x=24
x=6
Substitute x into any equation and then solve for y.
y=(6)-5=1
x=6, y=1
Hope that helps!
