Question

A 30.0-kgkg box is being pulled across a carpeted floor by a horizontal force of 230 NN , against a friction force of 210 NN . What is the acceleration of the box?

Answer 1

Answer:

The acceleration of the box is 0.67 m/s²

Explanation:

Given that,

Mass of box = 30.0 kg

Horizontal force = 230 N

Friction force = 210 N

We need to calculate the acceleration of the box

Using balance equation

$F-f_{k}=ma$

$a=\dfrac{F-f_{k}}{m}$

Where, F = horizontal force

$f_{k}$ =frictional force

m= mass of box

a = acceleration

Put the value into the formula

$a=\dfrac{230-210}{30}$

$a=0.67\ m/s^2$

Hence, The acceleration of the box is 0.67 m/s²