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2 years ago

In what direction would the particles in this wave move, relative to the direction of wave travel?

Physics

2 answers:

Setler79 [48]2 years ago

7 0

Everywhere particles dont stay in one place they move elsewhere

kompoz [17]2 years ago

7 0

Answer:

The wave is moving to the right, and the particles inside the wave (supposing that the wave is something like a piece of rope) are also moving up and down (in this way making the peaks and troughs of the wave), and remember that as the wave moves right, the particles also have a component moving to the right.

If we consider only the movement relative to the wave (so we are moving along with the wave) we ignore the right movement and only keep the up and down movement.

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A swimming pool has the shape of a right circular cylinder with radius 21 feet and height 10 feet. Suppose that the pool is full

AysviL [449]

Answer:

The water required to pump all the water to a platform 2 feet above the top of the pool is is 6061310.32 foot-pound.

Explanation:

Given that,

Radius = 21 feet

Height = 10 feet

Weighing = 62.5 pounds/cubic

Work = 4329507.37572

Height = 2 feet

Let's look at a horizontal slice of water at a height of h from bottom of pool

We need to calculate the area of slice

Using formula of area

$A=\pi r^2$

Put the value into the formula

$A=\pi\times21^2$

$A=441\pi\ feet^2$

Thickness of slice $t=\Delta h\ ft$

The volume is,

$V=(441\pi\times\Delta h)\ ft^3$

We need to calculate the force

Using formula of force

$F=W\times V$

Where, W = water weight

V = volume

Put the value into the formula

$F=62.5\times(441\pi\times\Delta h)$

$F=27562.5\pi\times\Delta h\ lbs$

We need to calculate the work done

Using formula of work done

$W=F\times d$

Put the value into the formula

$W=27562.5\pi\times\Delta h\times(10-h)\ ft\ lbs$

We do this by integrating from h = 0 to h = 10

We need to find the total work,

Using formula of work done

$W=\int_{0}^{h}{W}$

Put the value into the formula

$W=\int_{0}^{10}{27562.5\pi\\times(10-h)}dh$

$W=27562.5\pi(10h-\dfrac{h^2}{2})_{0}^{10}$

$W=27562.5\pi(10\times10-\dfrac{100}{2}-0)$

$W=4329507.37572$

To pump 2 feet above platform, then each slice has to be lifted an extra 2 feet,

So, the total distance to lift slice is (12-h) instead of of 10-h

We need to calculate the water required to pump all the water to a platform 2 feet above the top of the pool

Using formula of work done

$W=\int_{0}^{h}{W}$

Put the value into the formula

$W=\int_{0}^{10}{27562.5\pi\\times(12-h)}dh$

$W=27562.5\pi(12h-\dfrac{h^2}{2})_{0}^{10}$

$W=27562.5\pi(12\times10-\dfrac{100}{2}-0)$

$W=1929375\pi$

$W=6061310.32\ foot- pound$

Hence, The water required to pump all the water to a platform 2 feet above the top of the pool is is 6061310.32 foot-pound.

8 0

3 years ago

If a marble is released from a height of 10 meters how long would it take to hit the ground?

zlopas [31]

S = ut + 0.5at^2

10 = 0 + 0.5(9.81)t^2 {and if g = 10 then t^2 = 2 so t ~1.414} 

t^2 ~ 2.04 

t ~ 1.43 seconds

3 0

3 years ago

The following nuclear reaction is balanced. True False

elena-14-01-66 [18.8K]

I think its true for tht one!!

5 0

3 years ago

Read 2 more answers

What material is rare in the atmosphere of earth, but common in the atmospheres of mars and venus?

Oksanka [162]

The answer is carbon dioxide

4 0

3 years ago

A young boy is dragging his 10 kg stuffed animal by the tail at a constant velocity of 4 m/s. The coefficient of friction betwee

Daniel [21]

Answer:

if you multiply the coefficient to the denominator you will find that the percentage of increase is equal to your ending point

Explanation:

7 0

3 years ago