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Anni [7]
3 years ago
9

A card game is played in which the player wins if a face card is drawn​ (king, queen,​ jack) from a deck of 52 cards. If the pla

yer plays 10​ times, what is the expected number of wins for the​ player? Round your answer to two decimal places.
Mathematics
1 answer:
Over [174]3 years ago
5 0

Answer:

The expected number of wins for the​ player is 2.31

Step-by-step explanation:

No. of face cards = 12

total cards = 52

Probability of getting face card = \frac{\text{No. of face cards}}{\text{Total No. of cards}}

Probability of getting face card = \frac{12}{52}

The player plays 10​ times

Formula : E=np

n = no. of trials = 10

p = probability of success= \frac{12}{52}

E=expected number of wins

E=10(\frac{12}{52})

E=2.307

So,  the expected number of wins for the​ player is 2.31

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Answer:

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Step-by-step explanation:

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Let's say we'll mix "x" amount of the 80% solution, how much antifreeze is in it? well is just 80% of antifreeze, and the rest is something else.... what's 80% of "x"? so is (80/100)*x, or 0.8x.

likewise, the mixture will be a 70% solution, and let's say it adds up to "y" amount, so how much antifreeze is in it? well (70/100) * y or 0.7y.

\bf \begin{array}{lccclll}
&\stackrel{gallons}{amount}&\stackrel{\%}{quantity}&\stackrel{antifreeze}{quantity}\\
&------&------&------\\
\textit{80\% sol'n}&x&0.80&0.8x\\
\textit{10\% sol'n}&100&0.10&10\\
------&------&------&------\\
mixture&y&0.70&0.7y
\end{array}

so whatever "x" is, we know that x + 100 = y.

and we know that 0.8x + 10 = 0.7y.

\bf \begin{cases}
x+100=\boxed{y}\\
0.8x+10=0.7y\\
----------\\
0.8x+10=0.7\left( \boxed{x+100} \right)
\end{cases}
\\\\\\
0.8x+10=0.7x+70\implies 0.8x-0.7x=70-10\implies 0.1x=60
\\\\\\
x=\cfrac{60}{0.1}\implies x=600
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3 years ago
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4 years ago
A rectangle has a perimeter of 76 cm and length 31 cm what is its width
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Divide both sides by 2:

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The width is 7 cm.



6 0
4 years ago
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