Answer:
m = 2.31 Kg
Explanation:
given,
m₁ is the mass rest on the inclined plane = 1.5 Kg
inclination of plane = 30°
Kinetic friction = μ = 0.4
acceleration of the body = 2.68 m/s²
mass m is hanging = ?
using equation to solve
T - m₁g sin θ - μ m₁g cos θ = m₁ a
on the block on inclined plane there will be acting tension T on the string,
mg sin θ will be the force acting opposite to the tension on the string and a frictional force will be acting which will oppose moment which will be equal to μ m₁g cos θ
T = m₁(g sin θ + μ g cos θ + a )
T = 1.5 (9.8 x sin 30° + 0.4 x 9.8 x cos 30°+ 2.68 )
T = 16.46 N
now, forces on the other side of pulley
m g - T = m a
m (g - a ) = T
m = 2.31 Kg
Answer:
The value is
Explanation:
From the question we are told that
The mass of the Ping-Pong is
The terminal speed is
The drag force is
Generally the resultant force on the Ping- Pong is mathematically represented as
when terminal velocity is attained , the resultant force is zero so
=>
=>
=>
Answer:
0.122 m/s
Explanation:
mass of first train, m1 = 150,000 kg
initial velocity of first train, u1 = 0.3 m/s
mass of second train, m2 = 110,000 kg
initial velocity of second train, u2 = - 0.120 m/s
let the velocity of coupled mass after the collision is v.
Use the conservation of momentum
Momentum of trains before collision = Momentum of trains after collision
150000 x 0.3 - 110000 x 0.120 = (150000 + 110000)v
45000 - 13200 = 260000 v
31800 = 260000 v
v = 0.122 m/s
Thus, they travel with the speed of 0.122 m/s towards right after collision.
Two half-lives produce (1/2) x (1/2) = 1/4 of the decaying substance.
There would still be 400 atoms. But 300 would have thrown off
particles from their nucleuses, and only 100 would still be radioactive.