Answer:
231.98 mL
Explanation:
V₁ = Initial volume = 205 mL
V₂ = Final volume
P₁ = Initial pressure = 712 mmHg
P₂ = Final pressure = 750 mmhg (STP)
T₁ = Initial temperature = -44 °C = 229.15 K
T₂ = Final temperature = 273.15 K (STP)
From Combined gas law
Volume of the argon at STP is 231.98 mL
Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=
Temperature=T=
Pressure at sea level = P= 1 atm=
R is universal Gas Constant =8.314 J/mol.K
Formula:
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles