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2 years ago

The particle of 2 velocities 10m/s due east and 12m/S in the direction 30N/E. What is the resultant velocity and the direction?

Physics

1 answer:

Paha777 [63]2 years ago

8 0

Answer:

See below

Explanation:

East components are 10 and 12 cos 30 = 20.392 m/s

North component = 12 sin 30 = 6 m/s

Resultant velocity = sqrt ( 20.392^2 + 6^2) = <u>21.26 m/s </u>

direction arc tan (6/20.392) = <u>16.4 degrees N of east </u>

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