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Jet001 [13]
2 years ago
11

The particle of 2 velocities 10m/s due east and 12m/S in the direction 30N/E. What is the resultant velocity and the direction?

Physics
1 answer:
Paha777 [63]2 years ago
8 0

Answer:

See below

Explanation:

East components are   10    and    12 cos 30   = 20.392 m/s

North component =  12 sin 30 = 6 m/s

Resultant velocity = sqrt ( 20.392^2 + 6^2) = <u>21.26 m/s </u>

  direction   arc tan   (6/20.392) = <u>16.4 degrees N of east </u>

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3 years ago
A force of 14 N acts on a 5 kg object for 3 seconds.
DiKsa [7]

Answer: a) 42Nm b) 8.4m/s

Explanation:

Impulse is defined as object change in momentum.

Since Force = mass × acceleration

F = ma

Acceleration is the rate of change in velocity.

F = m(v-u)/t

Cross multiply

Ft = m(v-u)

Since impulse = Ft

and Ft = m(v-u)... (1)

The object change in velocity (v-u) = Ft/m from eqn 1

Going to the question;

a) Impulse = Force (F) × time(t)

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3 years ago
If you weigh 882 N on EARTH (HINT: What number do we ALWAYS use for gravity on Earth), what is your mass? ​
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4 0
3 years ago
Question #1: The visible part of the EM spectrum ranges from about 390 nanometers to about 720 nanometers. A nanometer (nm) is 1
mojhsa [17]

Answer:

The blue light has the highest energy.      

Explanation:

Body that is hot enough emits light as consequence of its temperature. For example, an iron bar in contact with fire will start to change colors as the temperature increases until it gets to a blue color. That its know as Wien's displacement law, which establishes that the peak of emission for the spectrum will be displaced to shorter wavelengths as the temperature increases.

The same scenario described above can be found in the star, a star with higher temperature will have a blue color and one with lower temperature will have a red color.

T = \frac{2.898x10^{-3} m. K}{\lambda max}  (1)

The energy of each wavelength can be determined by means of the following equation:

E = h\nu (2)

but \nu = \frac{c}{\lambda}, therefore:

E = \frac{hc}{\lambda}  (3)

     

Where h is the planck's constant and \nu is the frequency.

Notice that it is necessary to express the frequency in units of meters for a better representation of the energy.

\nu_{blue} = 400nm . \frac{1x10^{-9}m}{1nm} ⇒ 4x10^{-7}m

\nu_{red} = 720nm . \frac{1x10^{-9}m}{1nm} ⇒ 7.2x10^{-7}m

           

Case for the bluest light:

E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{4x10^{-7}m}                                                      

E = 4.96x10^{-19}J                                

                             

Case for the reddest light:    

     

E = \frac{(6.626x10^{-34}J.s)(3x10^{8}m/s)}{7.2x10^{-7}m}                                                        

     

E = 2.76x10^{-19}J                

                           

Equation 3 show that if the wavelength is lower the energy will be greater (inversely proportional).

Hence, according with the result and what was explained above, the blue light has the highest energy.

7 0
3 years ago
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