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sveta [45]
3 years ago
9

A retailer sold three cameras for rs 28500 and had a loss of 5%.find the cost price of each camera.

Mathematics
1 answer:
Len [333]3 years ago
3 0

Answer:10000

Step-by-step explanation:

Let price of one camera is =x

Price of 3 cameras=3x

Total loss=5\%

Hence The selling price=(1-0.05)\times3x

0.95\times 3x=28500\\\\x=\frac{28500}{0.95\times3}\\\\x=10000

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Answer:

The answer would be 7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6

Step-by-step explanation:

In order to find that answer, start by grouping all of the terms by their variable values. Ones that are the same should be combined.

8mn^5 - mn^5 = 7mn^5

2m^6 - 4m^6 = -2m^6

5m^2n^4 + 9m^2n^4 = 14m^2n^4

-m^3n^3 - 4m^3n^3 = -5m^3n^3

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Now we simply combine them all to get

7mn^5 - 2m^6 + 14m^2n^4 - 5m^3n^3 + n^6

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WILL GIVE BRAINLIEST a card is picked from the following card find the probability that the card drawn is purple
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Answer:

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Step-by-step explanation:

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If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

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