Answer:
Explanation:
Givens
m = 942
F = 6731
t = 21 seconds
vi = 0
vf = ?
Formula
F = m * (vf - vi ) / t
Solution
6731 = 942*(vf - 0)/21 Multiply both sides by 21
6731 * 21 = 942*vf
141351 = 942*vf Divide by 942
141351/942 = vf
vf = 151 m/s
<span> Let’s determine the initial momentum of each car.
#1 = 998 * 20 = 19,960
#2 = 1200 * 17 = 20,400
This is this is total momentum in the x direction before the collision. B is the correct answer. Since momentum is conserved in both directions, this will be total momentum is the x direction after the collision. To prove that this is true, let’s determine the magnitude and direction of the total momentum after the collision.
Since the y axis and the x axis are perpendicular to each other, use the following equation to determine the magnitude of their final momentum.
Final = √(x^2 + y^2) = √(20,400^2 + 19,960^2) = √814,561,600
This is approximately 28,541. To determine the x component, we need to determine the angle of the final momentum. Use the following equation.
Tan θ = y/x = 19,960/20,400 = 499/510
θ = tan^-1 (499/510)
The angle is approximately 43.85˚ counter clockwise from the negative x axis. To determine the x component, multiply the final momentum by the cosine of the angle.
x = √814,561,600 * cos (tan^-1 (499/510) = 20,400</span>
Answer:
That's almost the true
Explanation:
it does not happen all the time
