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dsp73
3 years ago
7

An outfielder throws a 1.1 kg baseball at a speed of 62 m/s and an initial angle of 12.3 ◦ . What is the kinetic energy of the b

all at the highest point of its motion? Answer in units of J.
Physics
1 answer:
Monica [59]3 years ago
6 0

Answer:

= 2,018.3 J

Explanation:

mass (m) = 1.1 kg

velocity (v) = 62 m/s

initial angle(θ) = 12.3°

kinetic energy = 0.5mv^{2}

where

  • m is the mass
  • v is the velocity, which has two components

      v = Vx + Vy  (horizontal component + vertical component)

      at the maximum height, velocity is 0, so Vy = 0 and v= Vx

      v = Vx = v.cosθ

      v = 62 x cos 12.3 = 60.6 m/s

therefore kinetic energy = 0.5mv^{2} = 0.5x1.1x60.6^{2}

= 2,018.3 J

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Answer:

t = 0.196 s

Explanation:

The speed of a pulse is determined by the characteristics of the medium, its density and its resistance to stress, as long as these remain the speed will be constant for which we can use the kinetic expressions of the uniform movement

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          t = x / v

calculate

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4 0
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