The dog house consists of two geometric objects, triangular prism and rectangular prism.
First, find the surface area of triangular prism
The triangular prism consists of
base of triangle (b) = 3 ft
height of triangle (h) = 2.5 ft
height of prism or length of rectangle (l) = 4 ft
side of triangle or width of rectangle (w) = 2.5 ft
Now, calculate the area
area of tp = area of two triangle + area of 2 rectangle
area of tp = (2 × 1/2 × b × h) + (2 × l × w)
area of tp = (2 × 1/2 × 3 × 2) + (2 × 4 × 2.5)
area of tp = 6 + 20
area of tp = 26 ft²
Second, find the surface area of rectangular prism
The rectangular prisms consists of
length (l) = 3 ft
width (w) = 4 ft
height (h) = 2 ft
Now, calculate the area
area of rp = area of back and front rectangle + area of left and right rectangle
area of rp = (2 × l × h) + (2 × w × h)
area of rp = (2 × 3 × 2) + (2 × 4 × 2)
area of rp = 12 + 16
area of rp = 28 ft²
Third, add both of the area
area = area of tp + area of rp
area = 26 + 28
area = 54 ft²
The area of the dog house is 54 ft²
Hey there!
Here's your answer: m<BDC=69
Here's how I got it:<ADC=112; <ADB and <BDC together form <ABD.
you would add 6x+7and 12x-3 together to equal 112; 18x+4=112, and solve for x
next substitute 6 for x, into m<BDC=12x-3, and simplify!
Hope this helps!
All you need to do here is know where and how to plug in the numbers. In each equation, you'll have an initial fee, and an hourly fee, so your equation will be
y = i + hx, where i = the initial fee, and h = the hourly fee
So, after plugging them in, here's what you get:
Doors Galore: y = 40 + 50x
G&H: y = 60 + 40x
Answer:
Step-by-step explanation:
(x+6)(x+4)(x-3)
= [(x+6)(x+4)](x-3)
= (x² + 4x + 6x + 24)(x - 3)
= (x² +10x + 24)(x - 3)
= x³ - 3x² + 10x² - 30x + 24x - 72
= x³ + 7x² - 6x - 72
