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Step2247 [10]
3 years ago
5

How many liters of water should be added to 18 liters of a 14% bleach solution so that the resulting solution contains only 10%

bleach?
Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

7.2 liters of water must be added to create a 10% bleach solution.

Step-by-step explanation:

18 liters times 14%, or 18 * 0.14, is 2.52. If we want bleach to be 10% of our solution, we can just multiply this number by 10 because 10% times 10 is 100%!! 2.52 * 10 is 25.2. To find how many liters of water you need to add you just find the difference. To do this you subtract your original from your new solution, so 25.2 - 18 = 7.2 liters of water need to be added.

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Answer:

42 1/7 degrees

Step-by-step explanation:

65+7x=360

7x=295

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3 years ago
If $5200 is invested at a rate of 8.6% compounded quarterly, how long will it take, to the nearest hundredth of a year, until th
dexar [7]

Answer:

t= 9.43\ years

Step-by-step explanation:

we know that    

The compound interest formula is equal to  

A=P(1+\frac{r}{n})^{nt}  

where  

A is the Final Investment Value  

P is the Principal amount of money to be invested  

r is the rate of interest  in decimal

t is Number of Time Periods  

n is the number of times interest is compounded per year

in this problem we have  

t=?\ years\\ P=\$5,200\\ r=8.6\%=8.6\100=0.086\\n=4\\A=\$11,600  

substitute in the formula above

11,600=5,200(1+\frac{0.086}{4})^{4t}  

11,600=5,200(1.0215)^{4t}  

(11,600/5,200)=(1.0215)^{4t}  

Applying log both sides

log(11,600/5,200)=log(1.0215)^{4t}  

applying property of logarithms

log(11,600/5,200)=(4t)log(1.0215)  

t=log(11,600/5,200)/[(4)log(1.0215)]

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4 years ago
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