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Step2247 [10]
3 years ago
5

How many liters of water should be added to 18 liters of a 14% bleach solution so that the resulting solution contains only 10%

bleach?
Mathematics
1 answer:
sergeinik [125]3 years ago
5 0

Answer:

7.2 liters of water must be added to create a 10% bleach solution.

Step-by-step explanation:

18 liters times 14%, or 18 * 0.14, is 2.52. If we want bleach to be 10% of our solution, we can just multiply this number by 10 because 10% times 10 is 100%!! 2.52 * 10 is 25.2. To find how many liters of water you need to add you just find the difference. To do this you subtract your original from your new solution, so 25.2 - 18 = 7.2 liters of water need to be added.

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Solve the system of equation below x+y+z=2 x-y+5z=6
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X + y + z = 2
x - y + 5z = 6

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x + 5z = 6

-5x -5z = -10
...x +5z = 6
---------------------
-4x = -4 *(-1)
4x = 4
x = 4/4
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1 + z = 2
z = 2 - 1
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x + y + z = 2
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S: {x, y, z} = {1, 0, 1}


8 0
3 years ago
Point b has coordinates (-8,15) and lies on the circle whose equation is x^2+y^2=289. If an angles is drawn in standard position
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Answer:

\cos \theta=-\dfrac{8}{17}

Step-by-step explanation:

Coordinates of Point b=(-8,15)

b lies on the circle whose equation is x^2+y^2=289

x^2+y^2=17^2

Comparing with the general form a circle with center at the origin: x^2+y^2=r^2

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For an angle drawn in standard position through point b,

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Therefore, the angle is in Quadrant II.

\cos \theta=\dfrac{Adjacent}{Hypotenuse} \\$Adjacent=-8\\Hypotenuse=17\\\cos \theta=\dfrac{-8}{17} \\\cos \theta=-\dfrac{8}{17}

8 0
2 years ago
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