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monitta
3 years ago
10

Five friends want to rent a go-cart track that costs $100. Each friend intends to contribute the same about. Susan used the five

-step problem-solving plan. After completing the solve step, how much money did she find that each friend will have to contribute to reach the goal? Enter you answer in the box.
Mathematics
2 answers:
elena-s [515]3 years ago
8 0

5 friends contribute x money to go to a cart that costs $100.
.
5x = 100
x = 100/5
x = 20
.
Each friend contributed $20 for the cart

Gemiola [76]3 years ago
6 0

20 dollars is ze answer


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Please help anyone and explain please
umka2103 [35]

So if you distribute 4 in the first parentheses, you get 12x+20y+8z.

Then you distribute 3 in the second parentheses. You'll get 3x-3z. That all equals 12x+20y+8z+3x-3z.

Now you have to start combining numbers with the same variable. Start with x. 12x+3x is 15x.

y has no other common variable, it's left alone.

8z-3z is 5z

All together now with the numbers in simpler form, the equation is 15x+20y+5z

Jenna's would be the right answer because when you distribute 5 in her answer you get 15x+20y+5z

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3 years ago
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dlinn [17]
One of the answers is equilateral because all of the sides are of equal length. 
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6 0
3 years ago
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Select the correct answer from each drop-down menu.
vazorg [7]

Answer:

Step 1: Distribute -2 to 5x and 8

Step 2: Subtract from both sides of the equation 6x

Step 3: Add to both sides of the equation  16

Step 4: Divide both sides of the equation by -16

Step-by-step explanation:

Step 1: Apply the Distributive Property. Then you must  distribute -2 to 5x and 8

Then:

-2(5x+8)=14+6x\\\\-10x-16=14+6x

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-10x-16-6x=14+6x-6x\\\\-16x-16=14

 Step 3: You must apply the Addition property of Equality and add 16 to both sides of the equation. Then:

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Step 4: You must apply the Division property of Equality and divide both sides by -16. Then:

\frac{-16x}{-16}=\frac{30}{-16}\\\\x=\frac{30}{-16}\\\\x=-\frac{15}{8}

6 0
3 years ago
Use the Remainder Theorem to find the remainder for (2x^3-3x^2+6)/(x-1) and state whether or not the binomial is a factor of the
Bezzdna [24]

Answer:

Remainder= 5, and the binomial (x-1) is not a factor of the given polynomial.

Step-by-step explanation:

Given polynomial is (2x^3-3x^2+6) , we have to divide this with a binomial [tex}(x-1)[/tex] using remainder theorem.

Remainder theorem says if (x-a) is a factor then remiander would be f(a)

Therefore for (x-1), \ {we find}\  f(1)}

f(1)=(2\times 1^3-3\times1^2+6)\\1^3 =1\\1^2=1\\Substituting \ this \ above\\f(1)= (2-3+6)=5

Thus the remainder is 5 and since it is not 0 , so the binomial (x-1) is not a factor of the given polynomial.

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