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2 years ago

The diagram shows the intersections of several straight roads. The avenues run parallel to each other.

Mathematics

1 answer:

Harlamova29_29 [7]2 years ago

5 0

Answer:

The answer is B: 226 ft

Step-by-step explanation:

Just did the assignment on edg

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I just want to make sure that this is correct:

JulsSmile [24]

Answer:

yes

Step-by-step explanation:

6 0

3 years ago

Helppp this is due in an hour!!

STatiana [176]

First you solve for the area of the unshaded triangle. Use the formula of area of triangle which is 1/2bh to find. 1/2(9)(4) = 18 cm^2. The area of the unshaded triangle is 18cm^2. Now we need to find the area of the rectangle. We can find that by using the formula for area of rectangle which is (b)(h). 12*4 = 48 cm ^2. Now that we have the area of the triangle and the area of the rectangle, we just need to subtract the area of the triangle from the area of the rectangle to get the area of the shaded region. 48 cm^2 - 18 cm^2 = 30 cm^2.

So our answer is: The area of the shaded region is 30 cm^2. In this case it’s option C or the third option for your quiz.

4 0

2 years ago

What is the median of the data set?

mojhsa [17]

The answer is
D. 4.........

8 0

2 years ago

The graph of $y = ax^2 + bx + c$ is shown below. Find $a \cdot b \cdot c$. (The distance between the grid lines is one unit.)

Savatey [412]

Answer:

$a\cdot b\cdot c=\frac{15}{4}$

Step-by-step explanation:

Vertex is the minimum or maximum point of parabola

Vertex of parabola is (h,k)

Therefore, from given graph (-3,-2) is the lowest point.

Vertex of parabola is at (-3,-2).

Standard equation of parabola

$y-k=a(x-h)^2$

Substitute the values

$y-(-2)=a(x-(-3))^2=a(x+3)^2$

$y+2=a(x+3)^2$

(-1,0) lies on the parabola.

Therefore, it satisfied the equation of parabola.

$0+2=a(-1+3)^2=4a$

$a=2/4=1/2$

Now, using the value of a

$y+2=1/2(x+3)^2=1/2(x^2+6x+9)$

$y+2=\frac{1}{2}x^2+3x+\frac{9}{2}$

$y=\frac{1}{2}x^2+3x+\frac{9}{2}-2$

$y=\frac{1}{2}x^2+3x+\frac{9-4}{2}$

$y=\frac{1}{2}x^2+3x+\frac{5}{2}$

By comparing with

$y=ax^2+bx+c$

We get

$a=\frac{1}{2}, b=3, c=5/2$

$a\cdot b\cdot c=\frac{1}{2}\times 3\times \frac{5}{2}$

$a\cdot b\cdot c=\frac{15}{4}$

7 0

2 years ago

Me puede ayudar con esto porfa.

dsp73

Answer:

La respuesta correcta es la opción d) 5 a 1.

Step-by-step explanation:

Para calcular la relación entre los ingresos de Mary en 2019 ( $I_{2019}$ ) con respecto a sus ingresos en 2018 ( $I_{2018}$ ), partimos de que los ingresos de Mary en 2019 fueron un 20% mayores que sus ingresos en 2018:

$I_{2019} = 20\% \: I_{2018}$

$I_{2019} = \frac{20}{100}I_{2018}$

$\frac{100}{20}I_{2019} = I_{2018}$

$5I_{2019} = I_{2018}$

Entonces, la relación entre los ingresos de Mary en 2019 es 5 veces los ingresos de Mary en 2018. Por lo tanto, la respuesta correcta es la opción d) 5 a 1.

Espero que te sea de utilidad!

4 0

2 years ago