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AlladinOne [14]
3 years ago
9

A delivery truck is transporting boxes of two sizes: large and small. The combined weight of a large box and a small box is 70 p

ounds. The truck is transporting 60 large boxes and 65 small boxes. If the truck is carrying a total of 4300 pounds in boxes, how much does each type of box weigh?
Mathematics
1 answer:
nikklg [1K]3 years ago
5 0
X = large boxes and y = small boxes

x + y = 70.....x = 70 - y
60x + 65y = 4300

60(70 - y) + 65y = 4300
4200 - 60y + 65y = 4300
5y = 4300 - 4200
5y = 100
y = 100/5
y = 20 <=== the small boxes weigh 20 lbs

x + y = 70
x + 20 = 70
x = 70 - 20
x = 50 <== and the large boxes weigh 50 lbs
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Answer:

t=40

Step-by-step explanation:

The sum of all angles in a triangle will always equal 180°. This means that:

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Let's solve this equation!

(2t-42)+(4t-49)+(2t-49) = 180

First we simplify what's on the left side:

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3 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
AURORKA [14]

Answer:

(−0.103371 ; 0.063371) ;

No ;

( -0.0463642, 0.0063642)

Step-by-step explanation:

Shift 1:

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Mean, m1 = 10.53 mm ; Standard deviation, s1 = 0.14mm

Shift 2:

Sample size, n2 = 25

Mean, m2 = 10.55 ; Standard deviation, s2 = 0.17

Mean difference ; μ1 - μ2

Zcritical at 95% confidence interval = 1.96

Using the relation :

(m1 - m2) ± Zcritical * (s1²/n1 + s2²/n2)

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Upper boundary :

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B.)

We cannot conclude that gasket from shift 2 are on average wider Than gasket from shift 1, since the interval contains 0.

C.)

For sample size :

n1 = 300 ; n2 = 250

(10.53-10.55) ± 1.96*sqrt(0.14^2/300 + 0.17^2/250)

Lower boundary :

-0.02 - 0.0263642 = −0.0463642

Upper boundary :

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7 0
3 years ago
Find the area of the irregularly-shaped hexagon below
Ber [7]

let each box length be 1

<em><u>for</u></em><em><u> </u></em><em><u>white</u></em><em><u> </u></em><em><u>triangle</u></em>

area = ½bh

=½(4)(2)

=4

<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>o</u></em><em><u>r</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>e</u></em><em><u> </u></em><em><u>t</u></em><em><u>r</u></em><em><u>i</u></em><em><u>a</u></em><em><u>n</u></em><em><u>g</u></em><em><u>l</u></em><em><u>e</u></em>

area=½(2)(3)

=3

<em><u>f</u></em><em><u>o</u></em><em><u>r</u></em><em><u> </u></em><em><u>b</u></em><em><u>l</u></em><em><u>u</u></em><em><u>e</u></em><em><u> </u></em><em><u>m</u></em><em><u>a</u></em><em><u>r</u></em><em><u>k</u></em><em><u>e</u></em><em><u>d</u></em><em><u> </u></em><em><u>b</u></em><em><u>o</u></em><em><u>x</u></em><em><u>e</u></em><em><u>s</u></em>

each of the box

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=1

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so the total area will be 16

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=23 square units

7 0
3 years ago
Read 2 more answers
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