The net force of a pair of balanced forces is zero
Answer:
Explanation:
The amplitude of the oscillation under SHM will be .5 m and the equation of
SHM can be written as follows
x = .5 sin(ωt + π/2) , here the initial phase is π/2 because when t = 0 , x = A ( amplitude) , ω is angular frequency.
x = .5 cosωt
given , when t = .2 s , x = .35 m
.35 = .5 cos ωt
ωt = .79
ω = .79 / .20
= 3.95 rad /s
period of oscillation
T = 2π / ω
= 2 x 3.14 / 3.95
= 1.6 s
b )
ω = 
ω² = k / m
k = ω² x m
= 3.95² x .6
= 9.36 N/s
c )
v = ω
At t = .2 , x = .35
v = 3.95 
= 3.95 x .357
= 1.41 m/ s
d )
Acceleration at x
a = ω² x
= 3.95 x .35
= 1.3825 m s⁻²
Answer:0.27*10^{6} (m)
Explanation:
with a wave we know that speed= wavelenght* frecuency so
wavelenght= 3*10^{7} / 109 = 0.27*10^{6} (m)
Answer:
The magnitude of change in momentum of the ball is
and impulse is also
Explanation:
Given:
Velocity of a pitched ball

Velocity of ball after impact

From the formula of change in momentum,

Here mass is not given in question,
Mass of ball is 
Change in momentum is given by,


Magnitude of change in momentum is

And impulse is given by


So impulse and
Therefore, the magnitude of change in momentum of the ball is
and impulse is also
We assume

(acceleration is constant. We apply the equation

where s is the distance to stop

. We find the acceleration from this equation

We know the acceleration, thus we find the distance necesssary to stop when initial speed is
