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Zina [86]
3 years ago
5

Need Help Please and Thank You). Question 1: Explain how longitudinal waves and transverse waves are similar to each other and d

ifferent from each other. Question 2) Compare and contrast reflection and refraction. Question 3) What does it mean that energy is neither created nor destroyed? ( Please No Plagiarism and Be 100% positive with your answer. Will Mark Brainliest. If you write anything down that doesn't contain to my question you will be reported. Need two answers.​
Physics
1 answer:
natulia [17]3 years ago
7 0

1) The longitudinal waves move in parallel direction to the source of vibration. The transverse waves move in perpendicular direction to the source of vibration . They are similar in the sense that energy is transferred in the form of waves.

2) Reflection occurs when waves bounce from a surface back toward the source. Refraction is when waves are deflected when the waves go through a substance.

3) The Law of Conservation of Energy

states that energy can neither be created

nor destroyed, it can only be transferred or

changed from one form to another.

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Which statement below concerning the photoelectric effect is true? View Available Hint(s) Which statement below concerning the p
kakasveta [241]
There is a threshold frequency for each metal, and only light of a frequency higher than this threshold causes electrons to be emitted from the metal surface.
8 0
3 years ago
Complete the statements about the law of conservation of momentum.
Svetllana [295]

Answer:

complete the statements

Explanation:

3 0
2 years ago
The distribution of total body protein in healthy adult men is approximately Normal, with mean 12.3 kg and standard deviation 0.
Sophie [7]

Answer:

P(12.25\leq x \leq 12.35 ) = 0.9876

Explanation:

given,

mean (μ) = 12.3 Kg

standard deviation (σ ) = 0.1

random sample = 25

probability between 12.25 and 12.35 kg

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{n}}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{\sqrt{25}}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{12.35-12.3}{\dfrac{0.1}{5}}\leq z)- P(\dfrac{12.25-12.3}{\dfrac{0.1}{5}}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{5 (12.35-12.3)}{0.1}\leq z)- P(\dfrac{5(12.25-12.3)}{0.1}\leq z)

P(12.25\leq x \leq 12.35 ) = P(\dfrac{2.5\leq z)- P(-2.5\leq z)

using z-table

P(12.25\leq x \leq 12.35 ) = 0.9938 - 0.0062

P(12.25\leq x \leq 12.35 ) = 0.9876

4 0
3 years ago
Which of the following sets of properties leads to a high degree of thermal shock resistance? (A) High fracture strength High th
Rina8888 [55]

Answer:  

The correct Answer is C) <u>High fracture strength,</u> <u>High Thermal Conductivity,</u> <u>Low modulus of elasticity,</u> <u>Low coefficient of thermal</u>                                                                                                                                                                                                                                              

Explanation:

The ability of a solid to withstand sudden changes in temperature either during heating or cooling is known or referred to as Thermal Shock Resistance (TSR).

Thermal shock resistance is one of the most crucial factors of performance in solids for high temperature environments that can cause thermal stresses and risks for thermal shock damage.

Examples are as of such environments are energy conversion systems, electronic devices and cutting tools.

A common way to evaluate TSR is to look for maximum jump in surface temperature which a material can sustain without cracking.  This is known as thermal conductivity.

Failure due to thermal shock can be prevented by;

  • Reducing the thermal gradient seen by the object, by changing its temperature more slowly or increasing the material's thermal conductivity
  • Reducing the material's coefficient of thermal expansion
  • upping its strength
  • Introducing built-in compressive stress, as for example in tempered glass and in some cases tempered plastic
  • reducing its Young's modulus
  • increasing its toughness, by crack tip blunting (i.e., plasticity or phase transformation) or crack deflection

Thermal conductivity is an intensive physical property of a material that relates the heat flow through the material per unit area to temperature gradient across the material. The thermal conductivity of a material is basically a measure of its ability to conduct heat.    

The other factor that contributes to a high degree of thermal shock is:

Fracture Strength: This is the ability of a material containing a crack to resist fracture or resist becoming brittle. For example, glass has a high strength, but the presence of a small fracture reduces the strength. Therefore, glass has low fracture resistance. Fracture toughness is an important consideration in hydraulic fracture design.

Modulus of Elasticity:

An object or substance's resistance to being deformed elastically (i.e., non-permanently) when a stress is applied to it is calculated  or measured by a quantity known as Elastic Modulus (also known as Young modulus of elasticity)

A stiff material has a high Young's modulus and changes its shape only slightly under elastic loads (e.g. steel or diamond). A flexible material has a low Young's modulus and changes its shape considerably (e.g. rubbers).

Coefficient of thermal expansion (CTE) this refers to how the rate of change in the  size of an object with respect of every degree change in temperature assuming that pressure remains the same. An object with low CTE is Fine Ceramics or Advanced Ceramics.

Cheers!

               

4 0
2 years ago
Find the product of 30−−√ and 610−−√. Express it in standard form (i.
Helen [10]
The product of √30 and √610 is 10√183.


√30  = √(2×3×5)
and √610 = √(2×5×61

Since 61 can't be factorised further.
Therefore, the value of √30×√610 is
= √(2×3×5×2×5×61)
= 2×5×√(3×61)
=10√183
4 0
3 years ago
Read 2 more answers
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