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ludmilkaskok [199]
2 years ago
13

We can always determine the recession velocity of a galaxy (at least in principle) from its redshift. but before we can use hubb

le's law, we must first calibrate it by:_________
Physics
1 answer:
pychu [463]2 years ago
7 0

Measuring the distance to many distant galaxy with a standard candle technique.

Hubble presented the observational evidence for one of science’s greatest discoveries—the expanding universe. Hubble showed that galaxies are receding away from us with a velocity that is proportional to their distance from us: more distant galaxies recede faster than nearby galaxies.

A redshift is an increase in the wavelength, and corresponding decrease in the frequency and photon energy, of electromagnetic radiation.

The standard candle technique is particularly valuable when studying very distant objects. Eventually, the effects of parallax stop working because things get too far away. However, since a standard candle depends on the inverse square law, it can reach much further as a result.

As long as we have instruments that can detect a standard candle and measure its brightness, it can be used to measure a distance.

therefore before measuring the recission velocity one must use standard candle technique to eliminate any parallax

learn more about parallax here:

brainly.com/question/1394541

#SPJ4

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You rapidly swirl a mixture of substances with different densities
borishaifa [10]
Having different densities being swirled rapidly will cause sedimentation. Sedimentation is the segmentation of the mixture creating layers of particles of these different densities. The process of rapid swirling is called differential centrifugation. An example use of this method is separation human blood into, red, platelet and white blood cells.
6 0
3 years ago
Look at the image to answer the question correctly.
r-ruslan [8.4K]

Answer:

1-  b: 2- a : 3- c : 4- d

Explanation:

it starts 2 move away from strting point, then no motion, then moves toward the start, the slows up.

3 0
2 years ago
You drop a steel ball bearing, with a radius of 2.40 mm, into a beaker of honey. Note that honey has a viscosity of 6.00 Pa/s an
Stells [14]

Answer:

The “terminal speed” of the ball bearing is 5.609 m/s

Explanation:

Radius of the steel ball R = 2.40 mm

Viscosity of honey η = 6.0 Pa/s

\text { Viscosity has Density } \sigma=1360 \mathrm{kg} / \mathrm{m}^{3}

\text { Steel has a density } \rho=7800 \mathrm{kg} / \mathrm{m}^{3}

\left.\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2} \text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^{2} \text { on Earth }\right)

While calculating the terminal speed in liquids where density is high the stokes law is used for viscous force and buoyant force is taken into consideration for effective weight of the object. So the expression for terminal speed (Vt)

V_{t}=\frac{2 \mathrm{R}^{2}(\rho-\sigma) \mathrm{g}}{9 \eta}

Substitute the given values to find "terminal speed"

\mathrm{V}_{\mathrm{t}}=\frac{2 \times 0.0024^{2}(7800-1360) 9.8}{9 \times 6}

\mathrm{V}_{\mathrm{t}}=\frac{0.0048 \times 6440 \times 9.8}{54}

\mathrm{V}_{\mathrm{t}}=\frac{302.9376}{54}

\mathrm{V}_{\mathrm{t}}=5.609 \mathrm{m} / \mathrm{s}

The “terminal speed” of the ball bearing is 5.609 m/s

7 0
3 years ago
is the rate at which ____________________ changes. (Velocity or Acceleration, velocity or acceleration)
Troyanec [42]

<u>Acceleration</u> is the rate at which <u>velocity</u> changes.

8 0
2 years ago
Two forces are acting on a wheelbarrow. One force is pushing to the right and an equal force is pushing to the left. What can yo
andreev551 [17]

-- As far as we know, the forces on the wheelbarrow are balanced.

-- That tells us that the net force on the wheelbarrow is zero, just
as if there were no forces acting on it at all.

-- That tells us that the wheelbarrow's acceleration is zero ... its
speed and direction of motion are not changing.

-- That tells us that the wheelbarrow is moving in a straight line
at a constant speed.  It's very possible that relative to us, the speed
may be zero, but we can't tell that from the given information.

6 0
3 years ago
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