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ludmilkaskok [199]
2 years ago
13

We can always determine the recession velocity of a galaxy (at least in principle) from its redshift. but before we can use hubb

le's law, we must first calibrate it by:_________
Physics
1 answer:
pychu [463]2 years ago
7 0

Measuring the distance to many distant galaxy with a standard candle technique.

Hubble presented the observational evidence for one of science’s greatest discoveries—the expanding universe. Hubble showed that galaxies are receding away from us with a velocity that is proportional to their distance from us: more distant galaxies recede faster than nearby galaxies.

A redshift is an increase in the wavelength, and corresponding decrease in the frequency and photon energy, of electromagnetic radiation.

The standard candle technique is particularly valuable when studying very distant objects. Eventually, the effects of parallax stop working because things get too far away. However, since a standard candle depends on the inverse square law, it can reach much further as a result.

As long as we have instruments that can detect a standard candle and measure its brightness, it can be used to measure a distance.

therefore before measuring the recission velocity one must use standard candle technique to eliminate any parallax

learn more about parallax here:

brainly.com/question/1394541

#SPJ4

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Increasing the two objects will cause the gravitational force between the objects to decrease.
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This statement is false. Increasing the two objects' mass (I'm guessing) will actually increase their gravitational force. This is because of the equation:

F_g =  \frac{Gm_1m_2}{d^2}

If the distance was increased, then the statement would be true, but since you are increasing mass, which is proportional to the Force of Gravity, you are in fact, increasing the gravitational force between the two objects.
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The speedometer in your car reads 55mi/h this represents ___ of the car
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instantaneous speed of the car

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Answer:

Video

Explanation:

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A uniformly charged conducting sphere of 1.1 m diameter has a surface charge density of 6.2 µC/m2. (a) Find the net charge on th
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Answer:

(a) q = 2.357 x 10⁻⁵ C

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Explanation:

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radius of the sphere, r = 1.1 / 2 = 0.55 m

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σ is the surface charge density

q = 4π(0.55)²(6.2 x 10⁻⁶)

q = 2.357 x 10⁻⁵ C

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Φ = q / ε

where;

Φ is the total electric flux leaving the surface of the sphere

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True

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