The answer you are looking for is B, hope this helps.
Answer:
p= 1.50289×10⁷ N/m²
Explanation:
Given
HA = (564 m)................(River Elevation)
HB = (2096 m).............(Village Elevation)
Area = A =(π/4){Diameter}² = (π/4){0.15 m}² = 0.017671 m²
ρ = (1 gram/cm³) = (1000 kg/m³)........(Water Density)
p(pressure)=?
Solution
p=PA - PB
p= ρ*g*HB - ρ*g*HA
p= (ρ*g)*(HB - HA)
p= (1000×9.81 )×{2096 - 564}
p= 1.50289×10⁷ N/m²
Answer:
The pressure is 6570 lbf/ft²
The temperature is 766 ⁰R
The velocity is 2746.7 ft/s
deflection angle behind the wave is 17.56⁰
Explanation:
Speed of air at initial condition:

γ is the ratio of specific heat, R is the universal gas constant, and T is the initial temperature.
initial mach number

then, 
based on the values obtained, read off the following from table;
P₂/P₁ = 3.285
T₂/T₁ = 1.473
Mₙ₂ = 0.6355
Thus;
P₂ = 3.285P₁ = 3.285(2000) = 6570 lbf/ft²
T₂ = 1.473T₁ = 1.473(520⁰R) = 766 ⁰R
Again; to determine the velocity and deflection angle, first we calculate the mach number.




