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mestny [16]
3 years ago
15

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge

about the joke material (denoted by K), and the familiarity with the jokes (denoted by F) using this formula:
Mathematics
2 answers:
Blababa [14]3 years ago
8 0

Answer:

L = f(J, K, F)

L = (JK²)/F

So, as the formula appears, the appropriate units will be option A.

Unit for number of laughs = (jokes*knowledge²) / familiarity

Just like the formula suggests.

Step-by-step explanation:

Complete Question

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: L = (JK²)/F

Select an appropriate unit for number of laughs:

A) (jokes*knowledge²) / familiarity

B) familiarity / (jokes*knowledge²)

C) familiarity² / (jokes*knowledge)

D) (jokes*knowledge) / familiarity²

Solution

L = f(J, K, F)

where

L = number of laughs

J = number of jokes

K = amount of knowledge about the joke material

F = familiarity with the jokes

Analysing how the dependent variable depends on each of the independent variables.

- Number of jokes

The number of laughs will increase with the number of jokes and vice versa. It can be stated that there is a direct variation between the number of laughs and number of jokes.

- Amount of knowledge about the joke material

The more one understands the joke material, the funnier the joke. In fact, the joke can be termed funnier when one understands the joke material deeply. The direct variation of number of laughs to knowledge about joke material isn't just enough, the number of laughs varying directly as the square of the knowledge of joke material seems more fitting.

- Familiarity with the joke

The more familiar one is with a joke, the less funny it is. Hence, it's an inverse relationship between number of laughs and the familiarity with the joke.

L = (JK²)/F

So, as the formula appears, the appropriate units will be

(jokes*knowledge²) / familiarity

Just like the formula suggests.

Hope this Helps!!!

erastova [34]3 years ago
4 0

The question is incomplete. Here is the complete question.

The number of laughs (denoted by L) can be defined as a function of the number of jokes (denoted by J), the amount of knowledge about the joke material (denoted by K) and the familiarity with the jokes (denoted by F) using this formula: L = \frac{J.K^{2} }{F}.

Select an appropriate unit for number of laughs:

(jokes*knowledge²) / familiarity

familiarity / (jokes*knowledge²)

familiarity² / (jokes*knowledge)

(jokes*knowledge) / familiarity²

Answer: Unit for number of laughs is (jokes*knowledge²) / familiarity

Step-by-step explanation: Number of laughs (L) is related to jokes (J), knowledge (K) and familiarity (F) according to the proportion: L = \frac{J.K^{2} }{F}

The unit for L will be: L = (jokes.knowledge²).familiarity⁻¹

or

L = \frac{jokes*knowledge^{2} }{familiarity}

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Answer:

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Step-by-step explanation:

{x}^{2}  - 2x - 15

{x}^{2}  - 5x + 3x - 15 = 0

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i hope it will help you!

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3 years ago
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5 0
3 years ago
5v + 7f =28.70 if f is 2.85
adell [148]
Hey!

First, let's write the problem.
5v+7\left(2.85\right)=28.7
Multiply 7 with 2.85.
5v+19.95=28.7
Subtract 19.95 from both sides.
5v+19.95-19.95=28.7-19.95
5v=8.75
Divide both sides by 5.
\frac{5v}{5}=\frac{8.75}{5}
v=1.75

Let me know if you have any questions regarding this problem!
Thanks!
-TetraFish
3 0
3 years ago
Read 2 more answers
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