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nasty-shy [4]
3 years ago
15

Evaluate 8y + y + 7 for y=4

Mathematics
2 answers:
bulgar [2K]3 years ago
7 0

Answer: 43

Step-by-step explanation:

AleksandrR [38]3 years ago
5 0
Hi there! The answer is 43

To evaluate the expression, we must plug in y=4 into the expression. We get the following:

8y + y + 7 = \\ 8 \times 4 + 4 + 7 =
Multiply first.

32 + 4 + 7 = \\ 36 + 7 = 43

The answer is 43.
~ Hope this helps you!
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On a coordinate plane, a rectangle has points (1, 2), (1, negative 2), (negative 4, negative 2), (negative 4, 2).
kondor19780726 [428]

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Step-by-step explanation:

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Read 2 more answers
How do you rationalize the numerator in this problem?
maw [93]

To solve this problem, you have to know these two special factorizations:

x^3-y^3=(x-y)(x^2+xy+y^2)\\ x^3+y^3=(x+y)(x^2-xy+y^2)

Knowing these tells us that if we want to rationalize the numerator. we want to use the top equation to our advantage. Let:

\sqrt[3]{x+h}=x\\ \sqrt[3]{x}=y

That tells us that we have:

\frac{x-y}{h}

So, since we have one part of the special factorization, we need to multiply the top and the bottom by the other part, so:

\frac{x-y}{h}*\frac{x^2+xy+y^2}{x^2+xy+y^2}=\frac{x^3-y^3}{h*(x^2+xy+y^2)}

So, we have:

\frac{x+h-h}{h(\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2})}=\\ \frac{x}{\sqrt[3]{(x+h)^2}+\sqrt[3]{(x+h)(x)}+\sqrt[3]{x^2}}

That is our rational expression with a rationalized numerator.

Also, you could just mutiply by:

\frac{1}{\sqrt[3]{x_h}-\sqrt[3]{x}} \text{ to get}\\ \frac{1}{h\sqrt[3]{x+h}-h\sqrt[3]{h}}

Either way, our expression is rationalized.

7 0
4 years ago
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