Answer:
Step-by-step explanation:
The work is define as the integral of the force times distance. So we have:
Now, we can write the force in terms of density.
V is the volume (V=2*1*1=2 m³)
So the work will be:
The limit of integration is between 0 and 0.5 because we want to pump half of the water out of the aquarium.
I hope it helps you!
Answer:
Step-by-step explanation:
Transformation rule for dilation:
, where k = scale factor
Given : Scale factor =
Parallelogram JKLM has vertices J(-1, 6), K(0, 9), L(6, −3), and M(3, −3)
Vertices after dilation:
Hence, the coordinates of the image if the parallelogram =
x*y' + y = 8x
y' + y/x = 8 .... divide everything by x
dy/dx + y/x = 8
dy/dx + (1/x)*y = 8
We have something in the form
y' + P(x)*y = Q(x)
which is a first order ODE
The integrating factor is
Multiply both sides by the integrating factor (x) and we get the following:
dy/dx + (1/x)*y = 8
x*dy/dx + x*(1/x)*y = x*8
x*dy/dx + y = 8x
y + x*dy/dx = 8x
Note the left hand side is the result of using the product rule on xy. We technically didn't need the integrating factor since we already had the original equation in this format, but I wanted to use it anyway (since other ODE problems may not be as simple).
Since (xy)' turns into y + x*dy/dx, and vice versa, this means
y + x*dy/dx = 8x turns into (xy)' = 8x
Integrating both sides with respect to x leads to
xy = 4x^2 + C
y = (4x^2 + C)/x
y = (4x^2)/x + C/x
y = 4x + Cx^(-1)
where C is a constant. In this case, C = -5 leads to a solution
y = 4x - 5x^(-1)
you can check this answer by deriving both sides with respect to x
dy/dx = 4 + 5x^(-2)
Then plugging this along with y = 4x - 5x^(-1) into the ODE given, and you should find it satisfies that equation.