Answer:
I think it's 3,6.....................
Answer:
a. 0
b. 4^1
c. 14
d. 8
Step-by-step explanation:
Answer:
There can be 14,040,000 different passwords
Step-by-step explanation:
Number of permutations to order 3 letters and 2 numbers (total 5)
(AAANN, AANNA,AANAN,...)
= 5! / (3! 2!)
= 120 / (6*2)
= 10
For each permutation, the three distinct (English) letters can be arranged in
26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways
For each permutation, the two distinct digits can be arranged in
10!/(10-2)! = 10!/8! = 10*9 = 90 ways.
So the total number of distinct passwords is the product of all three permutations,
N = 10 * 15600 * 90 = 14,040,000
Answer:
I think it's c tell me it i'm wrong
Step-by-step explanation:
they both have and so it would be times
<span>4p - 5 • (p + 6)
</span>-p - 30 = -1 • (p + 30)<span>
</span>
<span> -p - 30</span>
