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atroni [7]
2 years ago
14

Graphing rational functions

Mathematics
1 answer:
Debora [2.8K]2 years ago
5 0

Answer:

Opinion B

Step-by-step explanation:

hope that will help you

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Applying properties of Exponents in exercise,use the properties of exponents to simplify the expression.See example 1.
evablogger [386]

Answer: a) 15625, b) 0.2, c) 625, d) 0.008.

Step-by-step explanation:

Since we have given that

a) (5^2)(5^3)

As we know that

a^m\times a^n=a^{m+n}

So, it becomes,

5^2\times 5^3=5^{2+3}=5^6=15625

(b) (5^2)(5^{-3})

So, it becomes,

5^2\times 5^{-3}=5^{2-3}=5^{-1}=\dfrac{1}{5}=0.2

(c) (5^2)^2

As we know that

(a^m)^n=a^{mn}

So, it becomes,

5^{2\times 2}=5^4=625

(d) 5^{-3}

a^{-m}=\dfrac{1}{a^m}\\\\5^{-3}=\dfrac{1}{5^3}=\dfrac{1}{125}=0.008

Hence, a) 15625, b) 0.2, c) 625, d) 0.008.

4 0
3 years ago
2x + y = 3
sergejj [24]

Hey there!

First, multiply the second equation by -2 as the problem states. When you multiply the second equation by -2, you get:

-2x+4y=2

Now, add this equation to the first equation in which you simply combine like terms:

2x+y=3

+

-2x+4y=2

=

5y= 5

In conclusion, the correct answer would be the first choice.

4 0
3 years ago
Read 2 more answers
Need some help...........​
Anarel [89]

Answer:

The answer is to the question is 13

7 0
3 years ago
A professor has recorded exam grades for 20 students in his​ class, but one of the grades is no longer readable. If the mean sco
Ivenika [448]

Answer:

5

Step-by-step explanation:

To obtain the total score for all the 20 students, we multiply the average score by the number hence

Total score for all 20 is 81*20=1620

Similarly, for the 19 students, the sum of their total score equals the product of the average and number of students hence

Total score for 19 readable is 19*85=1615

The difference between these two total scores ie for 20 and 19 students equals to the value of unreadable score. Therefore,

Difference=1620-1615=5

Therefore, the value of unreadable score is 5

3 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
3 years ago
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