A
rational number is any number that can be written as the
ratio between two other numbers i.e. in the form

Part A:
An easy choice that makes sense is 7.8, right in the middle. To prove that it's rational we need to write it as a ratio. In this case we have

Part B:
We need a number that can't be written as a ratio (because it neither terminates nor repeats). Some common ones are

,

,

and

so it makes sense to try and use those to build our number. In this case

works nicely.
First one = 9x3=27
Second one 12x9=108
3rd one = 3x4=12
Idk what that last one is
Step-by-step explanation:
from the line above
P1 = -2
P2 = -1
P3 = 1/3
P4 = 2/3
P5 = 1 1/2 = 3/2
The product of P1 to P5,P
=> P = -2×-1×1/3×2/3×3/2 = 2/3
Steps:
1. Multiply the first line by 3 and the second by 2
3(3x + 2y= 4)
2(8x -3y=-6)
2. New lines are
9x + 6y= 12
16x + -6y=-12
3. Now add/subtract them
25x + 0= 0
25x=0
4. Divide by 25
X=0
5. To find y, substitute the 0 in the x in one of the equations
9x + 6y= 12
9(0) + 6y= 12
6y= 12
6. Divide by 6, your Y=2
7. X=0, Y=2
The initial value is 3 (when x=0), and the multiplier is 2, when x=2. The equation can be written as
.. y = 3*(2^(x/2))