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zzz [600]
3 years ago
7

How many moles are in 98.17 g of osmium?​

Chemistry
1 answer:
Nata [24]3 years ago
6 0

Answer:

0.5161 mol Os

Explanation:

Step 1: Find molar mass

Os (Osmium) - 190.2 g/mol

Step 2: Use Dimensional Analysis

98.17 \hspace{3} g \hspace{3} Os(\frac{1 \hspace{3} mol \hspace{3} Os}{190.2 \hspace{3} g \hspace{3} Os} ) = 0.516141 mol Os

Step 3: Simplify

We have 4 sig figs

0.516141 mol Os ≈ 0.5161 mol Os

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Answer:

gde

Explanation:

We are attempting to synthesize 1-butyne from 1-chlorobutane. Since 1-chlorobutane is a primary alkyl halide, 1-butene is formed when 1-chlorobutane is reacted with a bulky base such as t -BuOK or t -BuOH in presence of strong heat. This is an E2 reaction.

Secondly, the 1-butene is reacted with bromine in carbon tetrachloride. The vicinal dihalide (1,2-dibromobutane) is formed. This can now undergo further elimination reactions in the presence of sodamide and strong heat to yield 1-butyne which is the desired product. These reactions involve the elimination of the first HBr molecule to give an alkenyl bromide. A second elimination now gives the terminal alkyne.

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3 years ago
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2 years ago
How many moles of CCI are there in 78.2 g of CCI.?
vaieri [72.5K]

Answer:

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Explanation:

NOTE: Since no hydrogen is attached to the compound given in question above, it means the compound is CCl₄.

The number of mole present in 78.2 g of CCl₄ can be obtained as follow:

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Mole of CCl₄ = 78.2 / 154

Mole of CCl₄ = 0.508 mole

Therefore, 0.508 mole is present in 78.2 g of CCl₄

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2 years ago
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Explanation:

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