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kakasveta [241]
3 years ago
5

For an aqueous solution of hf, determine the van't hoff factor assuming 0% and 100% ionization, respectively. a solution is made

by dissolving 0.0100 mol hf in enough water to make 1.00 l of solution. at 22 °c, the osmotic pressure of the solution is 0.307 atm. what is the percent ionization of this acid?
Chemistry
1 answer:
Snowcat [4.5K]3 years ago
7 0
According to Osmotic pressure equation:

π = i M R T

When π =0.307 atm & M = 0.01 mol & R (constant)= 0.0821 L-atom/mol-K &
T= 22+273 = 295 Kelvin

So Van't half vector i = π / (MRT)
                                   = 0.307 / (0.01 * 0.0821 * 295)
                                   = 1.27 

When there is no dissociation, i = no. of moles of Hf in 1 L of solution = (1-X) 
and when there is a complete dissociation so it is equal 2X according to this equation


HF(aq) + H2O (L) ⇆ H3O (aq) + F (aq)
(1-X)                                X              X

∴ i = (1-X) + (2x)

 1.27 = 1+X
∴X= 1.27 - 1 = 0.27 
∴ the percent ionization of the acid X = 27 %
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3 years ago
A chemist must prepare 550 mL of hydrochloric acid solution with a pH of 1.60 at 25°C .
hammer [34]

<u>Answer:</u> The volume of concentrated hydrochloric acid solution is 1.73 mL

<u>Explanation:</u>

To calculate the hydrogen ion concentration of the solution, we use the equation:

pH=-\log[H^+]

We are given:

pH = 1.60

Putting values in above equation, we get:

1.60=-\log [H^+]

[H^+]=10^{-1.60}=0.0251M

To calculate the volume of the concentrated solution, we use the equation:

M_1V_1=M_2V_2

where,

M_1\text{ and }V_1 are the molarity and volume of the concentrated HCl solution

M_2\text{ and }V_2 are the molarity and volume of diluted HCl solution

We are given:

M_1=8.0M\\V_1=?mL\\M_2=0.0251M\\V_2=550mL

Putting values in above equation, we get:

8.0\times V_1=0.0251\times 550.0\\\\V_1=\frac{0.0251\times 550}{8.0}=1.73mL

Hence, the volume of concentrated hydrochloric acid solution is 1.73 mL

6 0
3 years ago
Please help!
Anna71 [15]

The compound that is most likely present when treated with bromine and the sample absorbs the red bromine color is ; Cycloheptene

<h3>What is cycloheptene </h3>

Cycloheptene is an unsaturated colorless oily liquid which is insoluble in water it absorbs Bromine when used in performing unsaturation test due it unsaturated nature.

The red bromine color will be absorbed when used to treat Cycloheptene but will not be absorbed when used to treat cycloheptane due to its saturated nature.  

Hence we can conclude that the compound that is present is Cycloheptene.

Learn more about Unsaturation : brainly.com/question/561845

5 0
3 years ago
For a single substance at atmospheric pressure, classify the following as describing a spontaneous process, a nonspontaneous pro
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Answer and Explanation:

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The process is spontaneous <u>above</u> the melting point.

b. Gas condensing below its condensation point  ⇒ Spontaneous

Below the condensation point, the subtance is liquid (it condenses)

c. Liquid vaporizing above its boiling point  ⇒ Spontaneous

A liquid vaporizes at a temperature above the boiling point, it passes from liquido to the gas state

d. Liquid freezing below its freezing point  ⇒ Spontaneous

A liquid freezes at a temperature below its freezeing point, it passes from the liquid to the solid state.

e. Liquid freezing above its freezing point  ⇒ Nonspontaneous

The freezing is spontaneous below the freezing point.

f. Solid melting above its melting point  ⇒ Spontaneous

A solid melts at a temperature above the melting point

g. Liquid and gas together at boiling point with no net condensation or vaporization  ⇒ Equilibrium system

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h. Gas condensing above its condensation point  ⇒ Nonspontaneous

The condensation is spontaneous at a temperature below the condensation point.

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5 0
3 years ago
Putting up 98 points! Will give medal
VladimirAG [237]

A calorimeter contains 500 g of water at 25°C.....

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The specific heat of water is 4.18 J/g-°C.

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= 4.18 J/g-°C * 500 g * (39.4°C - 25°C)

= 4.18*500*14.4

= 30096J

or approx. 30kJ

4 0
3 years ago
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