Mass of NO₂= 203.32 g
<h3>Further explanation</h3>
Given
99.0 L of NO₂
Required
Mass of NO₂
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol.
So mol NO₂ :
= 99 : 22.4
= 4.42
Mass :
= mol x MW
= 4.42 x 46 g/mol
= 203.32 g
High and low concentrations of hydrogen
The answer is the coefficient is "1".
C₅H₁₀, now you see that there is no number with this and when there is no number or digit, it means the coefficient is one.
we use the coefficients to balance the equation of the reaction in such a way that number of the atoms of the elements in the reactants are equal to the number of atoms of different elements in the product, so that both sides are equal and balanced.
Respuesta:
1.50 moles
Explicación:
Paso 1: Escribir la ecuación química ajustada para la descomposición del carbonato de calcio
CaCO₃ ⇒ CaO + CO₂
Paso 2: Calcular los moles correspondientes a 150 g de CaCO₃
La masa molar de CaCO₃ es 100.09 g/mol.
150 g × 1 mol/100.09 g = 1.50 mol
Paso 3: Calcular los moles de CO₂ producidos a partir de 1.50 moles de CaCO₃
La relación molar de CaCO₃ a CO₂ es 1:1.
1.50 mol CaCO₃ × 1 mol CO₂/1 mol CaCO₃ = 1.50 mol CO₂
Answer:
The answer to your question is 0.62 atm = 62.82 kPa = 471.2 mmHg
Explanation:
Data
P = 0.62 atm
P = ? kPa
P = ? mmHg
Process
1.- Look for the conversion factor of atm to kPa and mmHg
1 atm = 101.325 kPa
1 atm = 760 mmHg
2.- Do the conversions
1 atm ----------------- 101.325 kPa
0.62 atm ------------ x
x = (0,62 x 101.325) / 1
x = 62.82 kPa
1 atm ------------------ 760 mmHg
0.62 atm ------------ x
x = (0.62 x 760)/1
x = 471.2 mmHg